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loris [4]
4 years ago
12

Can an object with constant acceleration reverse its direction of travel? can it reverse its direction twice? in each case, expl

ain and give an example.
Physics
1 answer:
Kay [80]4 years ago
4 0

If an object is moving under constant acceleration then it is possible to reverse its direction once

Like when we throw an object upwards under the action of constant gravity then the object first moves upwards then stops after reaching maximum height and reverse its direction to move back.

now for the next case it is not possible to reverse the direction twice when an object moves under constant acceleration

so when once object reverse it direction then after that it comes in the direction of acceleration and then continue in the same direction for whole motion

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A ball is kicked from the top of a building with a velocity of 50 m/s and lands 165 m away from the base of the building.
Nadusha1986 [10]

The height of the building is 53.4 m (projectile motion)

Explanation:

The motion of the ball is a projectile motion, so it follows a parabolic path which consists of two independent motions:  

- A uniform motion (constant velocity) along the horizontal direction  

- An accelerated motion with constant acceleration (acceleration of gravity) in the vertical direction  

First of all, we consider the horizontal motion, which is a uniform motion at constant speed. The equation that gives the horizontal distance travelled is:

d=v_x t  

where:

v_x = 50 m/s is the horizontal velocity of the ball, which is constant since there are no forces in this direction

d = 165 m is the horizontal distance travelled by the ball

Solving for t, we find the time of flight:

t=\frac{d}{v_x}=\frac{165}{50}=3.3 s

Now we analyze the vertical motion: it is an accelerated motion, we can use the suvat equation

s=ut+\frac{1}{2}at^2  

where  

s is the vertical displacement, which is the height of the building

u = 0 is the initial vertical velocity of the ball

t = 3.3 s is the time of flight

a=g=9.8 m/s^2 is the acceleration of gravity  

Solving for s, we find the height of the building:

s=0+\frac{1}{2}(9.8)(3.3)^2=53.4 m

Learn more about projectile motion here:

brainly.com/question/8751410

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6 0
4 years ago
Which one of the following statements is true?
Vlad1618 [11]
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3 0
4 years ago
What did they call the bug that the astronauts brought back from the moon?
MAXImum [283]
This is a riddle meant to have a humorous effect.
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4 0
3 years ago
According to Kepler's Third Law, a solar-system planet that has an orbital radius of 4 AU would have an orbital period of about
NARA [144]

Answer:

Orbital period, T = 1.00074 years

Explanation:

It is given that,

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The orbital period of the planet can be calculated using third law of Kepler's. It is as follows :

T^2=\dfrac{4\pi^2}{GM}r^3

M is the mass of the sun

T^2=\dfrac{4\pi^2}{6.67\times 10^{-11}\times 1.989\times 10^{30}}\times (1.496\times 10^{11})^3    

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So, a solar-system planet that has an orbital radius of 4 AU would have an orbital period of about 1.00074 years.

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3 years ago
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