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kodGreya [7K]
3 years ago
15

The outermost shell of an atom in known as ??​

Chemistry
1 answer:
melisa1 [442]3 years ago
8 0

Answer:

<em>The</em><em> </em><em>a</em><em>n</em><em>s</em><em>w</em><em>e</em><em>r</em><em> </em><em>is</em><em> </em><em>valance</em><em> </em><em>shell</em><em>.</em>

<em>Valance</em><em> </em><em>shell</em><em> </em><em>is</em><em> </em><em>the</em><em> </em><em>outermost</em><em> </em><em>shell</em><em> </em><em>of</em><em> </em><em>an</em><em> </em><em>atom</em><em> </em><em>which</em><em> </em><em>contains</em><em> </em><em>valance</em><em> </em><em>electrons</em><em> </em><em>on</em><em> </em><em>it</em><em> </em><em>of</em><em> </em><em>an</em><em> </em><em>atom</em><em> </em><em>of</em><em> </em><em>an</em><em> </em><em>elements</em><em>. </em>

<em><u>Hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

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You are given a solution of HCOOH (formic acid) with an approximate concentration of 0.20 M and you will titrate this with a 0.1
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Answer:

\boxed{\text{36 mL}}

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\text{Moles of HCOOH} =\text{20.00 mL HCOOH } \times \dfrac{\text{0.20 mmol HCOOHl}}{\text{1 mL HCOOH}} = \text{4.00 mmol HCOOH}

3. Calculate the moles of NaOH.

\text{Moles of NaOH = 4.00 mmol HCOOH } \times \dfrac{\text{1 mmol NaOH} }{\text{1 mmol HCOOH}} = \text{4.00 mmol NaOH}

4. Calculate the volume of NaOH

c = \text{4.00 mmol NaOH } \times \dfrac{\text{1 mL NaOH }}{\text{0.1105 mmol NaOH }} = \textbf{36 mL NaOH }\\\\\text{The titration will require }\boxed{\textbf{36 mL of NaOH}}

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Π = iMRT ½

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