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Zanzabum
3 years ago
10

Benzene is a starting material in the synthesis of nylon fibers and polystyrene (styrofoam). Its specific heat capacity is 1.74

J/(g·K).
If 16.7 kJ of energy is absorbed by a 225-g sample of benzene at 20.0°C, what is its final temperature?

A) -22.7° C
B) 36.7° C
C) 42.7° C
D) 62.7° C
Chemistry
1 answer:
katovenus [111]3 years ago
6 0

Answer:

D

Explanation:

The amount of energy released or absorbed is equal the product of the mass, the specific heat capacity and the temperature change. The temperature change being the difference between the final and initial temperature.

Q = mc∆T

Q = heat energy (Joules, J) m = mass of a substance (kg) c = specific heat (units J/g∙K)

∆ is a symbol meaning "the change in" ∆T = change in temperature (Kelvins, K)

From the data provided in the question, we can deduce that:

Q = 16.7KJ = 16,700J

m = 225g

c = 1.74J/g.k

For the temperature, let the final temperature be f. This means our ∆T = f - 20

16,700 = 225 * 1.74 * (f - 20)

16700 = 391.5 (f - 20)

f - 20 = 16700/391.5

f - 20 = 42.7

f = 20 + 42.7 = 62.7

Hence the final temperature is 62.7 degrees Celsius

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its A

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Calculate the density of a water bottle with a mass of 4 grams and a volume of 100ml.
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3 years ago
How many grams of Al will be deposited from molten AlCl3 by a current of 15.0 amp flowing for 24.0 hr ( 1 Faraday = 96500 C)
zimovet [89]

Answer:

121 aprox.

Explanation:

mass/molar mass = Q/CF

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7 0
4 years ago
In nature, oxygen has three common isotopes. The atomic masses and relative abundances of these isotopes are given in the table
Vaselesa [24]

Answer: The average atomic mass of oxygen is 15.999 amu

Explanation:

Mass of isotope O-16 = 15.995 amu

% abundance of isotope O-16= 99.759 % = \frac{99.759}{100}=0.99759

Mass of isotope O-17 = 16.995 amu

% abundance of isotope O-17 = 0.037% = \frac{0.037}{100}=0.00037

Mass of isotope O-18 = 17.999 amu

% abundance of isotope O-18 = 0.204% = \frac{0.204}{100}=0.00204

Formula used for average atomic mass of an element :

\text{ Average atomic mass of an element}=\sum(\text{atomic mass of an isotopes}\times {{\text { fractional abundance}})

A=\sum[(15.995\times 0.99759)+(16.995\times 0.00037)+(17.999 \times 0.00204)]

A=15.999

Thus the average atomic mass of oxygen is 15.999 amu

5 0
3 years ago
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