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olga_2 [115]
3 years ago
15

What pressure will be necessary to compress 2 liters of a gas at 1 atm to a volume of 0.05 liters if the temperature remains con

stant
Chemistry
1 answer:
PtichkaEL [24]3 years ago
8 0
<h3>Answer:</h3>

40 atm

<h3>Explanation:</h3>
  • According to Boyle's law, the pressure and the volume of a fixed mass of a gas are inversely proportional at constant absolute temperature.
  • That is; P\alpha \frac{1}{V}
  • At varying pressure and volume,

P1V1 =P2V2

In this case,

Initial volume, V1 = 2 L

Initial pressure, P1 = 1 atm

New volume, V2 = 0.05 L

We are required to calculate the new pressure,

Rearranging the formula;

P2 = P1V1 ÷ V2

     = (1 atm × 2L) ÷ 0.05 L

     = 40 atm

Therefore, the pressure required is 40 atm

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A reaction proceeds with 2.72 moles of magnesium chlorate and 3.14 moles of sodium hydroxide. this is the equation of the reacti
den301095 [7]

The theoretical amount of each product obtained are:

  • 1.57 moles of Mg(OH)₂
  • 3.14 moles of NaClO₃

<h3>Balanced equation</h3>

Mg(ClO₃)₂ + 2NaOH —> Mg(OH)₂ + 2NaClO₃

<h3>How to determine the limiting reactant</h3>

From the balanced equation above,

1 mole of Mg(ClO₃)₂ reacted with 2 moles of NaOH

Therefore,

2.72 moles of Mg(ClO₃)₂ will react with = 2.72 × 2 = 5.44 moles of NaOH

From the calculation above, we can see that a higher amount (5.44 moles) of NaOH than what was given (3.14 moles) is needed to react completely with 2.72 moles of Mg(ClO₃)₂

Therefore, NaOH is the limiting reactant

<h3>How to determine the theoretical yield of Mg(OH)₂</h3>

From the balanced equation above,

2 moles of NaOH reacted to produce 1 mole of Mg(OH)₂

Therefore,

3.14 moles of NaOH will react to produce = 3.14 / 2 = 1.57 moles of Mg(OH)₂

Thus, the theoretical yield of Mg(OH)₂ is 1.57 moles

<h3>How to determine the theoretical yield of NaClO₃</h3>

From the balanced equation above,

2 moles of NaOH reacted to produce 2 mole of NaClO₃

Therefore,

3.14 moles of NaOH will also react to produce 3.14 moles of NaClO₃

Thus, the theoretical yield of NaClO₃ is 3.14 moles

Learn more about stoichiometry:

brainly.com/question/14735801

#SPJ4

8 0
2 years ago
A galvanic cell at a temperature of 42 degrees Celcius is powered by the following redox reaction:
seropon [69]

<u>Answer:</u> The cell voltage of the given reaction is 1.86 V

<u>Explanation:</u>

The given chemical equation follows:

3Cu^{2+}(aq.)+2Al\rightarrow 2Al^{3+}(aq.)+2Au(s)

<u>Oxidation half reaction:</u> Al(aq.)\rightarrow Al^{3+}(aq.)+3e^-;E^o_{Al^{3+}/Al}=1.66V       ( × 2)

<u>Reduction half reaction:</u> Cu^{2+}(aq.)+2e^-\rightarrow Cu(s);E^o_{Cu^{2+}/Cu}=0.16V       ( × 3)

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{cathode}-E^o_{anode}

Putting values in above equation, we get:

E^o_{cell}=0.16-(-1.66)=1.82V

To calculate the EMF of the cell, we use the Nernst equation, which is:

E_{cell}=E^o_{cell}-\frac{2.303RT}{nF}\log \frac{[Al^{3+}]^2}{[Cu^{2+}]^3}

where,

E_{cell} = electrode potential of the cell = ? V

E^o_{cell} = standard electrode potential of the cell = +1.82 V

n = number of electrons exchanged = 2

R = Gas constant = 8.314 J/mol Kl

T = temperature = 42^oC=[42+273]K=315K

F = Faraday's constant = 96500

[Al^{3+}]=1.63M

[Cu^{2+}]=3.43M

Putting values in above equation, we get:

E_{cell}=1.82-\frac{2.303\times 8.314\times 315}{2\times 96500}\times \log(\frac{(1.63)^2}{(3.43)^3})\\\\E_{cell}=1.86V

Hence, the cell voltage of the given reaction is 1.86 V

4 0
3 years ago
A student hypothesizes that water from infrequently used school faucets contains more chemical impurities than the water from fr
Sauron [17]
The different school faucets (frequently and infrequently used) are the manipulated or independent variable. The exact school faucet being tested is chosen (in a sense, manipulated) to test a particular effect or in this case, the presence of <span>more chemical impurities.</span>
6 0
3 years ago
What is the formula unit for a compound made from Pb4+ and oxygen?
dem82 [27]

Answer : The formula unit of compound will be, PbO_2

Explanation :

As we know that one atom of oxygen contains (2-) charge and one atom of lead contains (4+) charge. So, to balance the of charges of lead, the 2 oxygen atoms combine with the 1 lead atom. Thus, the compound formed will be, PbO_2.

That means, when Pb^{4+} combine with oxygen that is, O^{2-}, it gives PbO_2 by the criss-cross method.

Criss cross method : It is a method of determining the chemical formula.

The formula unit is a shown below.

7 0
3 years ago
The specific heat capacity of titanium is 0.523j/g c what is the heat capacity of 2.3g of titanium
kodGreya [7K]

Answer:

1.2029 J/g.°C

Explanation:

Given data:

Specific heat capacity of titanium = 0.523 J/g.°C

Specific heat capacity of 2.3 gram of titanium = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

1 g of titanium have 0.523 J/g.°C specific heat capacity

2.3  × 0.523 J/g.°C

1.2029 J/g.°C

8 0
3 years ago
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