The molarity of (HNO₃) that was used if 2.00 L must be used to prepare 4.5 L of a 0.25M HNO₃ solution is 0.563 M
<u><em>calculation</em></u>
This is calculated usind M₁V₁=M₂V₂ formula
where,
M₁( molarity ₁) = ?
V₁( volume ₁) = 2.00 L
M₁ (molarity ₂) = 0.25M
V₂( volume₂) = 4.5 L
make M₁ the subject of the formula by diving both side of the formula by V₁
M₁ is therefore = M₂V₂/V₁
M₁ =[ (0.25 M x 4.5 L) / 2.00 L ] =0.563 M
Answer:
Sodium hydroxide
Explanation:
Sodium hydroxide ( NaOH ) -
Sodium hydroxide is an inorganic compound , and is also called caustic soda and lye .
It is an ionic compound , which is white in color and is in solid state .
The cation and anion of this salt are the sodium cation Na⁺ and the hydroxide anions OH⁻ .
<u>It is highly basic in nature and is soluble in water , and when left open in air it can readily absorb moisture from the air , to form a hydrated sodium hydroxide .</u>
Answer:
When an atom gains or loses energy, the energy of an electron can change.
An electron in an atom can move from one energy level to another when the atom gains or loses energy.
Explanation:
The possible energies that electrons in an atom
can have are called energy levels.
• An electron cannot exist between energy levels.
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Answer:
2.34 molality
Explanation:
Mole weight of KOH ( using periodic table ...rounded to 3 s.f.) =
56.1 gm/mole
Number of moles in 43.2 g
43.2 g / 56.1 gm / mole =.770 mole
molality = .770 mole / .329 kg = 2.34 m