Answer:
Explanation:
The law of conservation of mass states that "mass in a system remains constant and that the mass of the product is remains the same as that of the reactants".
Law of conservation of energy states that "energy is neither created nor destroyed in the course of chemical or physical change but can be transformed from one form to another".
Let us properly write the equation:
CH₄ + 2O₂ → CO₂ + 2H₂O
For the conservation of mass:
C has 1mole on both sides
H has 4mole on both sides
O has 4 mole on both sides
For energy, during combustion process, the methane CH₄ burns to liberate heat energy. This is an energy conversion process in which chemical energy in methane releases heat energy.
The number of atoms : N = 2.709 x 10⁴⁶
<h3>Further explanation</h3>
Given
4.5 x 10²² moles of CO₂
Required
The number of atoms
Solution
The mole is the number of particles(molecules, atoms, ions) contained in a substance
1 mol = 6.02.10²³ particles
Can be formulated
N=n x No
N = number of particles
n = mol
No = Avogadro's = 6.02.10²³
Input the value :
N = 4.5 x 10²² x 6.02 x 10²³
N = 2.709 x 10⁴⁶
Consumption of a synthetic material being increased, leads to an associated negative impacts to Earth required to produce it is a True statement.
<h3>What is a Synthetic material?</h3>
There are the materials which are made by humans through chemical synthesis which are usually done in factories.
The production of this type of materials leads to the emission of chemicals and other gases which are harmful and negatively impacts the environment.
Read more about Synthetic material here brainly.com/question/24357817
Answer:
Explanation:
The combustion reaction of Octane is:
To calculate the mass of CO₂ and H₂O produced, we need to know the mass of octane combusted.
We calculate the mass of Octane from the given volume and density, using the following <em>conversion factors</em>:
Now we<u> convert 1.24 gallons to mL</u>:
- 1.24 gallon *
4693.4 mL
We <u>calculate the mass of Octane</u>:
- 4693.4 mL * 0.703 g/mL = 3.30 g Octane
Now we use the <em>stoichiometric ratios</em> and <em>molecular weights</em> to <u>calculate the mass of CO₂ and H₂O</u>:
- CO₂ ⇒ 3.30 g Octane ÷ 114g/mol *
* 44 g/mol = 10.19 g CO₂
- H₂O ⇒ 3.30 g Octane ÷ 114g/mol *
* 18 g/mol = 4.69 g H₂O
