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Leokris [45]
3 years ago
10

Chemistry students were testing compounds in an aqueous solution to see which one had the strongest electrical current. There ar

e three beakers each with a different compound. The first beaker and the second beaker lit the light bulbs brightly. The third beaker did not light up the bulb. With the information that is provided, what is the best explanation for the first and second beaker being the strongest electrolytes?
A)The first and second beakers contain a solution that partially dissociates the ions. These ions create an electrical current. The third beaker solution completely dissociates the ions. It is a strong electrolyte.

B)The first and second beakers contain a solution that completely dissociates the ions. These ions create an electrical current. The third beaker solution does not dissociate ions. It is a nonelectrolyte.

C)The first and second beakers contain a solution that does not dissociate ions. These ions create an electrical current. The third beaker solution completely dissociates the ions. It is a strong electrolyte.

D)The first and second beakers contain a solution that completely dissociates the ions. These ions do not create an electrical current. The third beaker solution does completely dissociates the ions. It is a strong electrolyte.
Chemistry
2 answers:
jasenka [17]3 years ago
8 0

Answer:

B)The first and second beakers contain a solution that completely dissociates the ions. These ions create an electrical current. The third beaker solution does not dissociate ions. It is a nonelectrolyte.

Explanation:

Electrolytes dissociate ions. They are also conductors. Since the first 2 bulbs light up strongly, we can assume that the ions completely dissociated. Since the 3rd did not light up, it is a nonelectrolyte.

Pavel [41]3 years ago
6 0

Answer:

The first and second beakers contain a solution that completely dissociates the ions. These ions create an electrical current. The third beaker solution does not dissociate ions. It is a nonelectrolyte.

Explanation:

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3 Cu + 8HNO3 g 3 Cu(NO3)2 + 2 NO + 4 H2O
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Considering the reaction stoichiometry, the amount of moles of NO that is produced when 27 moles of HNO₃ react is 6.75 moles.

<h3 /><h3>Reaction stoichiometry</h3>

The balanced reaction is:

3 Cu + 8 HNO₃ → 3 Cu(NO₃)₂ + 2 NO + 4 H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:  

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<h3>Amount of moles of NO produced</h3>

It is possible to determine the the amount of moles of NO produced by a rule of three: if by stoichiometry 8 moles of HNO₃ produce 2 moles of NO, if 27 moles of HNO₃ react how many moles of NO will be formed?

amount of moles of NO=\frac{27 moles of HNO_{3} x 2 moles of NO}{8 moles of HNO_{3}}

<u><em>amount of moles of NO= 6.75 moles</em></u>

In summary, the amount of moles of NO that is produced when 27 moles of HNO₃ react is 6.75 moles.

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