Pythagoras theorem:
hypotenuse²=leg₁²+leg₂²
Data:
leg₁=4 u
leg₂=7 u
Therefore:
hypotenuse²=(4 u)²+(7 u)²
hypotenuse²=16 u²+49 u²
hypotenuse²=65 u²
hypotenuse=√(65 u²)≈8.06 u
Answer: the length of the hypotenuse is 8.06 u
Answer:
To find the surface area of a rectangular solid, remember that each face is a rectangle, so its area is the product of its length and its width. Find the area of each face that you see and then multiply each area by two to account for the face on the opposite side.
Distance/Speed = Time
Distance=1,071 Speed=63 Time=x
1,071/63 = x
17 = x
Answer:
A rectangle has a length 6m less than twice its width. when 5 m are added to the width, the resulting figure is a square with an area of 256m^2. find the distance of the original rectangle
width:: x
length:: 2x-6
-------
New width:: x+5
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Equation:
(x+5)^2 =256 =16
16 is the original length
Answer:
see below
Step-by-step explanation:
the point-slope equation is
y-1 = 3/2 (x+4)