The correct option is B.
Single replacement reaction is a type of chemical reaction, in which one element is substituted for another element in a compound. There are usually two reactants, one is a pure element and the other one is an aqueous compound. The products formed is usually made up of another pure element and a new compound. In the option B, you will notice that, in the reactant part, Mg is a pure element while in the product side, H2 is a pure element.
Explanation:
The given balanced reaction is as follows.

It is given that mass of ammonium nitrate is 86.0 kg.
As 1 kg = 1000 g. So, 86.0 kg = 86000 g.
Hence, moles of
present will be as follows.
Moles of
= 
= 
= 1074.42 mol
Therefore, moles of
,
and
produced by 1074.42 mole of
will be as follows.
Moles of
= 
= 537.21 mol
Moles of
= 
= 1074.42 mol
Moles of
= 
= 2148.84 mol
Therefore, total number of moles will be as follows.
537.21 mol + 1074.42 mol + 2148.84 mol
= 3760.47 mol
According to ideal gas equation, PV = nRT. Hence, calculate the volume as follows.
PV = nRT
1 atm \times V = 3760.47 mol \times 0.0821 L atm/mol K \times 580 K[/tex] (as
= 307 + 273 = 580 K)
V = 179066.06 L
Thus, we can conclude that total volume of the gas is 179066.06 L.
Answer is: 25.84 milliliters of sodium metal.
Balanced chemical reaction: 2Na + 2H₂O → 2NaOH + H₂.
d(Na) = 0.97 g/mL; density of sodim.
m(NaOH) = 43.6 g; mass of sodium hydroxide.
n(NaOH) = m(NaOH) ÷ M(NaOH).
n(NaOH) = 43.6 g ÷ 40 g/mol.
n(NaOH) =1.09 mol; amount of sodium hydroxide.
From chemical reaction: n(NaOH) : n(Na) = 2 : 2 (1: 1).
n(Na) = 1.09 mol.
m(Na) = 1.09 mol · 23 g/mol.
m(Na) = 25.07 g; mass of sodium.
V(Na) = m(Na) ÷ d(Na).
V(Na) = 25.07 g ÷ 0.97 g/mL.
V(Na) = 25.84 mL.