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Natali [406]
4 years ago
12

Determine the kinetic energy of a 3.2 kg roller coaster car that is moving with a speed of 15.6 m/s.

Physics
1 answer:
Alex Ar [27]4 years ago
6 0

Answer:389.4 joules

Explanation:

kinetic energy=ke

Mass=m=3.2kg

Velocity=v=15.6 m/s

Ke=(m x v x v)/2

ke=(3.2 x 15.6 x 15.6)/2

Ke=778.752/2

Ke=389.4

Kinetic energy is 389.4 joules

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Answer:

The correct answer is - 200000 J

Explanation:

We use the formula of kinetic energy:

The formula to calculate kinetic energy is,

Here,

Ec =1/2 x  m x v^2

The mass of the roller coaster is,  m  =  1000  k g

The speed of the roller coaster is, v = 20.0 m/s

 Therefore,

Ec=1/2 x 1000kg x (20m/s)^2 = 200.000Joule

200,000J

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Answer:

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Explanation:

                                                                                                                                                                                     

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Here in order to find out the distance between two planes after 3 hours can be calculated by the concept of relative velocity

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here

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d = v* t

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so the magnitude of the distance is given as

d = \sqrt{2982.36^2 + 138.9^2}

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