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xeze [42]
3 years ago
12

A mixture of two compounds, A and B, was separated by extraction. After the compounds were dried, their masses were found to be:

119 mg of compound A and 97 mg of compound B. Both compounds were recrystallized and weighed again. After recrystallization, the mass of compound A was 83 mg and the mass of compound B was 79 mg. Calculate the percent recovery from recrystallization for both compounds.
Chemistry
1 answer:
Arlecino [84]3 years ago
3 0

Answer:

The percent recovery from re crystallization for both compounds A and B is 69.745 and 81.44 % respectively.

Explanation:

Mass of compound A in a mixture  = 119 mg

Mass of compound A after re-crystallization = 83 mg

Percent recovery from re-crystallization :

\frac{\text{Mass after re-crystallization}}{\text{Mass before re-crystallization}}\times 100

Percent recovery of compound A:

\frac{83 mg}{119 mg}\times 100=69.74\%

Mass of compound B in a mixture  = 97 mg

Mass of compound B after re-crystallization = 79 mg

Percent recovery of compound B:

\frac{79 mg}{97 mg}\times 100=81.44\%

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The simplest whole number ratio of the atoms of the elements in a specific compound is shown by the empirical formula for that compound. When the mass of each component of a compound or its % composition by mass is known, an empirical formula may typically be computed.

% composition is equal to (mass of an element minus mass of the compound) / 100%.

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% Vanadium composition: (20.38 g/23.58 g) 100%

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Learn more about empirical formula here brainly.com/question/13058832

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