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MatroZZZ [7]
3 years ago
9

3% Hydrogen Peroxide has an oral LD50 of 900 mg/kg. Acetic Acid has an oral LD50 of 3310 mg/kg. Which one is more hazardous to c

onsume
Chemistry
1 answer:
Maurinko [17]3 years ago
7 0
LD50 is defined as the lethal dose 50% which describes the amount of material required to kill 50% of the testing population. It is given in units of mg of chemical per kg of bodyweight of the recipient. 

Comparing hydrogen peroxide and acetic acid, we see that peroxide has a lower LD50 of 900 mg/kg, with acetic acid having LD50 = 3310 mg/kg. When comparing LD50 values, the smaller value will be the more toxic compound. What this means is that in this case, a smaller amount of peroxide is required to kill 50% of the testing population compared to acetic acid.

Therefore, 3% hydrogen peroxide is more hazardous to consume.
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How many atoms of chlorine are there in 16.5 g of iron (iii) chloride?
MrRa [10]
Fecl3 has a RFM of 56 + (35.5 * 3) = 162.5

so find out its moles 16.5 ÷ 162 5 = aprox. 0.1M

then there is a 1 : 3 ratio so 0.1 * 3 = 0.3

then times that by the avogado constant which is 6.02×10^23

0.3 × 6.02×10^23 = ans

hope that helps
7 0
4 years ago
What reaction conditions most effectively conver a cabocxylic acid to a methly ester?
VLD [36.1K]

Answer:

Esterification reaction

Explanation:

When we have to go from an acid to an ester we can use the <u>esterification reaction</u>. On this reaction, an alcohol reacts with a carboxylic acid on acid medium to produce an ester and water. (See figure).  

In this case, we need the <u>methyl ester</u>, therefore we have to choose the <u>appropriate alcohol</u>, so we have to use the <u>methanol</u> as reactive if we have to produce the methyl ester.

7 0
3 years ago
I really need help it's urgent help ! Don't ignore it .Your work will be appreciated and don't spam
gtnhenbr [62]

ツ here your answer

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  • A)Potassium bromide(aq) + Barium iodide(aq) → Potassium iodide(aq) + Barium bromide(s)

  • 2KBr(aq)+BaI2(aq) → 2KI(aq)+BaBr2(s)

  • B)Balance the Chemical Equation for the reaction of calcium carbonate with hydrochloric acid: 
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<em><u>M</u></em><em><u>a</u></em><em><u>r</u></em><em><u>k</u></em><em><u> </u></em><em><u>m</u></em><em><u>e</u></em><em><u> </u></em><em><u>i</u></em><em><u>n</u></em><em><u> </u></em><em><u>b</u></em><em><u>r</u></em><em><u>a</u></em><em><u>i</u></em><em><u>n</u></em><em><u>l</u></em><em><u>i</u></em><em><u>s</u></em><em><u>t</u></em>

8 0
3 years ago
You put two open cans of soda on the table. You took one can from the refrigerator and the other from your car. When you open th
sladkih [1.3K]
The correct answer from the choices given is the last option. The can from the <span> car will lose the carbon more quickly because there are fewer solute–solvent collisions. The can in the car has a lower temperature than the one in the refrigerator. At low temperature, the solubility of carbon dioxide in the liquid decrease therefore particles would tend to be in the vapor phase and escape from the liquid.</span>
6 0
3 years ago
The mole fraction of iodine, i2, dissolved in dichloromethane, ch2cl2, is 0.115. what is the molal concentration, m, of iodine i
german
The molality of a solute is equal to the moles of solute per kg of solvent. We are given the mole fraction of I₂ in CH₂Cl₂ is <em>X</em> = 0.115. If we can an arbitrary sample of 1 mole of solution, we will have:

0.115 mol I₂

1 - 0.115 = 0.885 mol CH₂Cl₂

We need moles of solute, which we have, and must convert our moles of solvent to kg:

0.885 mol x 84.93 g/mol = 75.2 g CH₂Cl₂ x 1 kg/1000g = 0.0752 kg CH₂Cl₂

We can now calculate the molality:

m = 0.115 mol I₂/0.0752 kg CH₂Cl₂
m = 1.53 mol I₂/kg CH₂Cl₂

The molality of the iodine solution is 1.53.
5 0
3 years ago
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