Number 1 is incorrect, the genotypes are given to you. You need to use GG and gg. The outcome would be 100% Gg.
Number 2 is incorrect, the genotypes are given to you. You need to use Gg and Gg. The outcome would be 25% gg, 25% GG, and 50% Gg.
Number 3 is incorrect, the genotypes are given to you. You need to use TT and tt. The outcome would be 100% Tt.
Number 4 is incorrect, the genotypes are given to you. You need to use RR and rr. The outcome would be 100% Rr.
Please read the directions and use the genotypes they give you! The information is all there for you, you just need to put it in correctly. If you're still having trouble understanding how to do this, feel free to message me and I'd be happy to help you.
<span>7.39 ml
For this problem, simply divide the mass of mercury you have by it's density.
100 g / 13.54 g/ml = 7.3855 ml
Since we only have 3 significant digits in 100., you need to round the result to 3 significant digits. So
7.3855 ml = 7.39 ml</span>
Answer:
A. The pressure will increase 4 times. P₂ = 4 P₁
B. The pressure will decrease to half its value. P₂ = 0.5 P₁
C. The pressure will decrease to half its value. P₂ = 0.5 P₁
Explanation:
Initially, we have n₁ moles of a gas that occupy a volume V₁ at temperature T₁ and pressure P₁.
<em>What would happen to the gas pressure inside the cylinder if you do the following?</em>
<em />
<em>Part A: Decrease the volume to one-fourth the original volume while holding the temperature constant. Express your answer in terms of the variable P initial.</em>
V₂ = 0.25 V₁. According to Boyle's law,
P₁ . V₁ = P₂ . V₂
P₁ . V₁ = P₂ . 0.25 V₁
P₁ = P₂ . 0.25
P₂ = 4 P₁
<em>Part B: Reduce the Kelvin temperature to half its original value while holding the volume constant. Express your answer in terms of the variable P initial.</em>
T₂ = 0.5 T₁. According to Gay-Lussac's law,
<em>Part C: Reduce the amount of gas to half while keeping the volume and temperature constant. Express your answer in terms of the variable P initial.</em>
n₂ = 0.5 n₁.
P₁ in terms of the ideal gas equation is:
P₂ in terms of the ideal gas equation is:
Answer:
There is no picture, how can we help?
Explanation:
Answer:This would be heterozygous, so both dominant and recessive alleles are written.
Explanation:Heterozygous means that the dominant and recessive alleles are written genotypically.