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White raven [17]
3 years ago
7

36. Write the SHORTCUT electron configuration for Caesium (Cs) which is element #55.

Chemistry
1 answer:
miv72 [106K]3 years ago
6 0

Answer:

Cesium. Full electron configuration of cesium: 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d10 5s2 5p6 6s1. xenon ← cesium → barium

Explanation:

most include 36. :-]

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Calculate the change in energy of an atom that emits a photon of wavelength 2.21 meters. (Planck’s constant is 6.626 x 10-34 jou
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3 years ago
Two properties of non-metallic elements and their
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2 years ago
Write a chemical equation for the reaction that occurs in the following cell: Cu|Cu2+(aq)||Ag+(aq)|Ag. Of the two metals, copper
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Answer:

Answer is given below.

Explanation:

Anode is that electrode where oxidation occurs. Cathode is that electrode where reduction occurs.

In cell representation, half cell present left to salt-bridge notation(\parallel ) is anodic system and another half cell present right to salt-bridge notation(\parallel ) is cathodic system.

So anode is Cu and cathode is Ag.

oxidation: Cu-2e^{-}\rightarrow Cu^{2+}(aq.)

[reduction: Ag^{+}+e^{-}\rightarrow Ag]\times 2

-----------------------------------------------------------------------------------------------

chemical equation: Cu+2Ag^{+}(aq.)\rightarrow Cu^{2+}(aq.)+2Ag

Oxidizing agent is that species which takes electron from another species. Here Ag^{+}(aq.) takes electron from Cu. Hence Ag^{+}(aq.)  is the oxidizing agent.

Reducing agent is that species which gives electron to another species. Here Cu gives electron to Ag^{+}(aq.) . Hence Cu  is the reducing agent.

6 0
3 years ago
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