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White raven [17]
3 years ago
7

36. Write the SHORTCUT electron configuration for Caesium (Cs) which is element #55.

Chemistry
1 answer:
miv72 [106K]3 years ago
6 0

Answer:

Cesium. Full electron configuration of cesium: 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d10 5s2 5p6 6s1. xenon ← cesium → barium

Explanation:

most include 36. :-]

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if  a substance has a ph greater than  7 (Ph>7) the substance is said to be a base

if a  substance has a Ph equal to 7(Ph=7)  the substance is said to be neutral
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Homeostasis subheading<br> The maintenance of stable internal conditions is called
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Answer:

<h3>homeostasis</h3>

•the maintenance of a stable internal environment

<u><em>Hope </em><em>this</em><em> helps</em><em> </em><em>:</em><em>)</em></u>

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Natural gas (CH4) has a molar mass of 16.0 g/mole. You started out the day with a tank containing 200.0 g of natural gas. At the
hodyreva [135]

Considering the definition of molar mass, the moles of gas used are 10.625 moles.

<h3>Definition of molar mass</h3>

The molar mass of substance is a property defined as its mass per unit quantity of substance, in other words, molar mass is the amount of mass that a substance contains in one mole.

<h3>Amount of moles used</h3>

Natural gas has a molar mass of 16.0 g/mole.

You started out the day with a tank containing 200.0 g of natural gas.  So, you can apply the following rule of three: If by definition of molar mass 16 grams are contained in 1 mole, 200 grams are contained in how many moles?

amount of moles at the beginning=\frac{200 gramsx1 mole}{16 grams}

<u><em>amount of moles at the beginning= 12.5 moles</em></u>

At the end of the day, your tank contains 30.0 g of natural gas. So, you can apply the following rule of three: If by definition of molar mass 16 grams are contained in 1 mole, 30 grams are contained in how many moles?

amount of moles at the end=\frac{30 gramsx1 mole}{16 grams}

<u><em>amount of moles at the end= 1.875 moles</em></u>

The number of moles used will be the difference between the number of moles used initially and the contents at the end of the day.

moles used= amount of moles at the beginning - amount of moles at the end

moles used= 12.5 moles - 1.875 moles

<u><em>moles used= 10.625 moles</em></u>

<u><em /></u>

Finally, the moles of gas used are 10.625 moles.

Learn more about molar mass:

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#SPJ1

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