The part that moves are called anti-nodes. The stationary pars are nodes
Answer:
a = 2.5 m/s^2
Explanation:
u = 0
v = 25
t = 10
(using first eq. of motion)
a = (v - u) /t
a = (25 - 0) /10
a = 25/10
a = 2.5 m/s^2
The voltage in the resistor is 63 V
Explanation:
We can solve the problem by applying Ohm's law, which states the relationship between voltage, current and resistance in a resistor:
where
V is the voltage
R is the resistance
I is the current
For the resistor in this problem, we have:
I = 0.42 A is the current
is the resistance
Substituting into the equation, we find the voltage needed:
Learn more about voltage and current:
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Answer:
a) t = 11.407 s, b) x = 175.66 m, v = c) v = 30.80 m / s
Explanation:
a) This is a kinematics exercise, let's write the equation of each vehicle
car
x = x₀ + v₀ t + ½ a t²
Let's fix our reference system at the point where the car is, indicate that the car stops from rest vo = 0
x₀ = v₀ = 0
we substitute
x = ½ a t²
truck
x₂= v₀ t
v₀ = 15.4 m / s
at the point where they are, their positions are equal
½ a t² = vo t
t = 2 vo / a
calculate us
t = 2 15.4 / 2.70
t = 11.407 s
b) the distance to reach it
x = ½ to t²
x = ½ 2.70 11.407²
x = 175.66 m
c) the speed of the car is
v = vo + a t
vo = 0
v = at
v = 2.70 11.407
v = 30.80 m / s
