Answer:
B
Explanation:
Given:-
- The charge of the test particle q = 3.0 * 10^-9 C
- The force exerted by the metal sphere F = 6.0 * 10^-5 N
Find:-
The magnitude and direction of the electric field
strength at this location?
Solution:-
- The relationship between the electrostatic force F exerted by the metal sphere on the test-charge and the Electric Field strength E at the position of test charge is given by:
F = E*q
- Using the data given we can determine E:
E = F / q
E = (6.0 * 10^-5) / (3.0 * 10^-9)
E = 20,000 N/C
- The direction of electric field is given by the net charge of the source ( metal sphere). The metal sphere is negative charge hence the direction of Electric Field strength E is directed towards the metal sphere.
Answer:
0.42°
Explanation:
Using Snell's law of refraction which states that the ratio of the angle of sin of incidence to angle of sine of refraction is equal to a constant for a given pair of media. Mathematically,
Sin(i)/sin(r) = n
n is the refractive index of the medium
FOR VIOLET LIGHT:
n = 2.46
i = 51°
r = ?
To get r, we will use the Snell's law formula.
2.46 = sin51°/sinr
Sinr = sin51°/2.46
Sinr = 0.316
r = sin^-1(0.316)
rv = 18.42°
FOR RED LIGHT:
n = 2.41
i = 51°
r = ?
To get r, we will use the Snell's law formula.
2.41 = sin51°/sinr
Sinr = sin51°/2.41
Sinr = 0.323
r = sin^-1(0.323)
rd = 18.84°
The angular separation between these two colors of light in the refracted ray will be the difference between there angle of refraction.
Angular separation = rd - rv
= 18.84° - 18.42°
= 0.42°
Answer:
Explanation:
Due to change in the position of 3 kg mass , the moment of inertia of the system changes , due to which angular speed changes . We shall apply conservation of angular momentum , because no external torque is acting .
Initial moment of inertia I₁ = M R² = 3 x 1 ² = 3 kg m²
Final moment of inertia I₂ = M R² = 3 x .3 ² = 0.27 kg m²
Applying law of conservation of angular momentum
I₁ ω₁ = I₂ ω₂
Putting the values ,
3 x .75 = .27 x ω₂
ω₂ = 8.33 rad / s
New angular speed = 8.33 rad /s .
The mass of the football player is 250 kg.
<u>Explanation:</u>
Momentum is defined as the product of mass and velocity. So here the velocity (v) is given as 10 m/s and the momentum is given as 2500 kg m /s. So we can determine the mass (m) of the player by substituting the known terms in the formula of determining momentum as shown below.
As we know the value of momentum and velocity, the mass can be found as,
Thus, the mass of the football player is found to be 250 kg.
