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3 years ago

Select all the correct answers.

Physics

2 answers:

Phantasy [73]3 years ago

8 0

Answer:

When water freezes, it's volume INcreases, which naturally results in a DEcrease in it's density. That's why cubes and bergs float.

Explanation:

I'm pretty sure that water is the only known substance that behaves this way. Which is lucky for us, because if it didn't, then life on Earth would be impossible. Oceans and lakes would freeze from the bottom up. Once! And then they would never thaw, because the sun could never cut through the layer of warm water on top, to melt the ice below.

Mamont248 [21]3 years ago

7 0

When water freezes, it's volume INcreases, which naturally results in a DEcrease in it's density. That's why cubes and bergs float.

I'm pretty sure that water is the only known substance that behaves this way. Which is lucky for us, because if it didn't, then life on Earth would be impossible. Oceans and lakes would freeze from the bottom up. Once! And then they would never thaw, because the sun could never cut through the layer of warm water on top, to melt the ice below.

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A set of four capacitors are attached to a 12V battery in the circuit shown below. All capacitances are measured in milli-Farads

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The amount of electric charge that resides on each capacitor once it is fully charged is 0.37 C.

<h3>Total capacitance of the circuit</h3>

The total capacitance of the circuit is calculated as follows;

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1/Ct = 1/8 + 1/7.5

1/Ct = 0.25833

Ct = 3.87 mF

Capacitors is parallel;

Ct = 3.87 mF + 12 mF + 15 mF

Ct = 30.87 mF

Ct = 0.03087 F

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Q = CV

Q = 0.03087 x 12

Q = 0.37 C

Thus, the amount of electric charge that resides on each capacitor once it is fully charged is 0.37 C.

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I just need number 2

il63 [147K]

We will apply the conservation of linear momentum to answer this question.

Whenever there is an interaction between any number of objects, the total momentum before is the same as the total momentum after. For simplicity's sake we mostly use this equation to keep track of the momenta of two objects before and after a collision:

m₁v₁ + m₂v₂ = m₁v₁' + m₂v₂'

Note that v₁ and v₁' is the velocity of m₁ before and after the collision.

Let's choose m₁ and v₁ to represent the bullet's mass and velocity.

m₂ and v₂ represents the wood block's mass and velocity.

The bullet and wood will stick together after the collision, so their final velocities will be the same. v₁' = v₂'. We can simplify the equation by replacing these terms with a single term v'

m₁v₁ + m₂v₂ = m₁v' + m₂v'

m₁v₁ + m₂v₂ = (m₁+m₂)v'

Let's assume the wood block is initially at rest, so v₂ is 0. We can use this to further simplify the equation.

m₁v₁ = (m₁+m₂)v'

Here are the given values:

m₁ = 0.005kg

v₁ = 500m/s

m₂ = 5kg

Plug in the values and solve for v'

0.005×500 = (0.005+5)v'

v' = 0.4995m/s

v' ≅ 0.5m/s

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2 years ago