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3 years ago

What is the kinetic energy of a 200kg boat moving at 2.7m/s?

Physics

2 answers:

n200080 [17]3 years ago

4 0

Answer:

<h3>729 Joules</h3>

Explanation:

Kinetic energy is 1/2mv²

where m is the mass of the object

v is the velocity

From the question

m = 200kg

v = 2.7m/s

Kinetic energy is

1/2 × 200 × 2.7²

= 729 Joules

Hope this helps you

sasho [114]3 years ago

3 0

729 joules is what I think is right

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Determine the mechanical energy of this object a 1-kg ball rolls on the ground at <br> m/s

dedylja [7]

Mechanical energy = potential energy + kinetic energy
The ball is on the ground so it has no potential energy. that's all i know.

8 0

3 years ago

A typical nuclear fission power plant produces about 1.00 GW of electrical power. Assume the plant has an overall efficiency of

mamaluj [8]

Answer:

mass consumed by 235U each day = 2 kg

Explanation:

electrical power produced = 1 GW = 1 × 10⁹ × (6.24151 × 10¹⁸ ) eV

= 6.24151× 10²¹ MeV/s

thermal energy = 0.420 * 250 = 105 MeV

$\dfrac{1 GW}{150 MeV}= \dfrac{6.24151\times 10^{21}}{105}$

= 5.94 × 10¹⁹ fission/second

=5.94 × 10¹⁹× 24 × 60 ×60)

= 5.13 × 10²⁴ fission/day

mu = 235.04393 × 1.660× 10 ⁻²⁷ = 390.1729× 10⁻²⁷ Kg

M = mu ×5.13 × 10²⁴

= 390.1729× 10⁻²⁷ ×5.13 × 10²⁴

M = 2 kg(approx.)

mass consumed by 235U each day = 2 kg

3 0

3 years ago

Which statement is true? A. A resistor alters current and a switch turns current on and off B. A resistor measures voltage, and

alina1380 [7]

Answer:

A. A resistor alters current and a switch turns current on and off

Explanation:

Resistor is the passive component that reduces the flow of current. Switch is the electrical device that turns on or off the current by closing and opening the electrical circuit.

Thus option A. A resistor alters current and a switch turns current on and off is correct.

3 0

3 years ago

A 4.50-kg wheel that is 34.5 cm in diametet rotates through an angle of 13.8 rad as it slows down uniformly from 22.0 rad/s to 1

lisabon 2012 [21]

Answer:

$\alpha =10.93radian/sec^2$

Explanation:

We have given given the final angular velocity $\omega _{final}=13.5rad/sec$

And $\omega _{initial}=22rad/sec$

Displacement $\Theta =13.8radian$

We have to find the angular acceleration $\alpha$

According to law of motion $\omega _{final}^2=\omega _{initial}^2+2\alpha \Theta$

So $13.5^2=22^2+2\times \alpha \times 13.8$

$\alpha =-10.93radian/sec^2$

In question we have tell about magnitude only so $\alpha =10.93radian/sec^2$

4 0

3 years ago

Automobile which is being towed at constant velocity up the incline using the cable at c. The automobile has a mass of 5 mg and

Simora [160]

The value of the normal reaction force will be 4.65 kN and 31.76 kN.

<h3>What is force?</h3>

Force is defined as the push or pull applied to the body. Sometimes it is used to change the shape, size, and direction of the body. Force is defined as the product of mass and acceleration. Its unit is Newton.

The normal force on the car is,Na= Nb =1 kN

The force of the cable on the car is,F=1 kN

The force of the gravity is,W=mg

The balancing equation of force;

$\rm N_A+N_B+F sin \theta_2 -mg cos \theta_2 =0 \\\\ \rm -Fcos \theta_2 +mg sin \theta_1 =0 \\\\ Fcos \theta_2 \times a -F sin \theta_2 \times b -mg cos \theta_1 \times c -mg sin \theta_1 \times e +N_B (c+d)=0 \\\\ N_A+N_B+F sin 30^0 - 5 \times 9.81 cos 30^0 =0 \\\\ -$

Putting the value further;

$\rm N_A+N_B+F sin 30^0 - 5 \times 9.81 cos 30^0 =0 \\\\ -F cos 30^0 + 9.81 sin 20^0 =0 \\\\ F cos 30^ 0 (0.6)-F sin30^0 (1.5)-(5 \times 10^6) \times 9.81 \times cos 20^0 (1)-(5)(9.81)sin 20^0 +N_B \times 1.75 =0$

Solving the equation, we get;

$\rm F_A = 19.37 \ kN \\\\ N_A=4.65 \ kN \\\\ N_B=31.76 \ kN$

Hence, the value of the normal force swill be 4.65 kN and 31.76 kN.

To learn more about the force, refer to the link;

brainly.com/question/26115859

#SPJ4

4 0

2 years ago