What is the value of 10 + (-4)? Possible answer's' 6 -14 -6 14

(MULTIPLE CHOICE QUESTION)

weeeeeb [17]

Answer:

Transitive property is used in step 4.

Step-by-step explanation:

Transitive property states that if

$a = b \\b = c\\ then\\a = c$

Here we have

$\angle 5 \cong \angle 1\\\angle 1 \cong \angle 3\\then\\\angle 3 \cong \angle 5$

3 0

3 years ago

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Hadley buys 7 boxes of markers with 8

Natalka [10]

Answer:

128

Step-by-step explanation:

7×8=56

12×6=72

56+72=128

7 0

4 years ago

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Autum school holding a voleturing challeng. Students are encouraged to volunteer for at least 1 1/2 hours per week. Volenteers a

Pani-rosa [81]

Given :

Challenge given is to volunteer for about 1 1/2 hours per week .

Autum did at a rate of 6 3/4 hours per week .

To Find :

The comparison ( ratio ) her volunteers rate with the challenge rate .

Solution :

Simplifying challenge rate in in normal fraction , $1\dfrac{1}{2}=\dfrac{2+1}{2}=\dfrac{3}{2}$ .

Also , simplifying her rate , $6\dfrac{3}{4}=\dfrac{(6\times 4)+3}{4}=\dfrac{27}{4}$ .

Now , ratio of his work by challenge is :

$R=\dfrac{\dfrac{27}{4}}{\dfrac{3}{2}}\\\\\\R=\dfrac{27\times 2}{4\times 3}\\\\R=\dfrac{9}{2}$

Therefore , the ratio is 9/2 or 4 1/2 .

Hence , this is the required solution .

8 0

4 years ago

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For a certain candy, 20% of the pieces are yellow, 15% are red, 20% are blue, 20% are green, and the rest are brown. a

OLEGan [10]

Answer:

Step-by-step explanation:

Based on the question we are given the percentages of each of the types of candies in the bag except for brown. Since the sum of all the percentages equals 75% and brown is the remaining percent then we can calculate that brown is (100-75 = 25%) 25% of the bag. Now we can show the probabilities of getting a certain type of candy by placing the percentages over the total percentage (100%).

Brown: $\frac{25}{100}$
Yellow or Blue: $\frac{20}{100} +\frac{20}{100} = \frac{40}{100}$ ....add the numerators

Not Green: $\frac{80}{100}$ .... since the sum of all the rest is 80%

Stiped: $\frac{25}{100}$ .... there are 0 striped candies.

Assuming the ratios/percentages of the candies stay the same having an infinite amount of candy will not affect the probabilities. That being said in order to calculate consecutive probability of getting 3 of a certain type in a row we have to multiply the probabilities together. This is calculated by multiplying the numerators with numerators and denominators with denominators.