While playing basketball in PE class, Logan lost his balance after making a lay-up and colliding with the padded wall behind the
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Answer: The force acting on the proton of charge 1.5 x10-19 C moving with velocity 1.5 x10-19 C under the influence of a magnetic field of 0.7 T will be 3.15×10^-13 N.
Explanation: To find the answer we need to know more about the Lorentz magnetic force.
<h3>What is the Lorentz magnetic force acting on the proton?</h3>- Consider a proton of charge q moving with a velocity v in a magnetic field, then the Lorentz magnetic force exerted on the proton can be expressed as,
F= q (v× B)
where,
is the angle between v and B.
- In the question, it is given that,
because, from the question it is clear that the proton is moving along x axis and the magnetic field is along the y axis.
- Thus, we can find the force acting on the proton as,
Thus, we can conclude that the Lorentz force acting on the proton will be 3.15×10^-13 N.
Learn more about the Lorentz magnetic force here:
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