Not sure the precise concept of "normal observation", but I assume that is observed by "eyes".
Eye observation is basically macroscopic, but when you use a mark, which can be regarded as a point of mass, then it goes to microscopic.
Mark is a reference point which you can compare the relative position change, but with your eyes, first you cannot notice microscopic changes, second the eyes cannot precisely set a stable reference point.
Answer:
200 N
Explanation:
Power = work / time
Work = force × distance
Therefore:
Power = force × distance / time
100 W = F × 10 m / 20 s
F = 200 N
He exerted 200 N.
Newton's 3rd law: The ball exerts a force on the bat that is equal and opposite to the force exerted by the bat on the ball.
The planet that Punch should travel to in order to weigh 118 lb is Pentune.
<h3 /><h3 /><h3>The given parameters:</h3>
- Weight of Punch on Earth = 236 lb
- Desired weight = 118 lb
The mass of Punch will be constant in every planet;
![W = mg\\\\m = \frac{W}{g}\\\\m = \frac{236}{g}](https://tex.z-dn.net/?f=W%20%3D%20mg%5C%5C%5C%5Cm%20%3D%20%5Cfrac%7BW%7D%7Bg%7D%5C%5C%5C%5Cm%20%3D%20%5Cfrac%7B236%7D%7Bg%7D)
The acceleration due to gravity of each planet with respect to Earth is calculated by using the following relationship;
![F = mg = \frac{GmM}{R^2} \\\\g = \frac{GM}{R^2}](https://tex.z-dn.net/?f=F%20%3D%20mg%20%3D%20%5Cfrac%7BGmM%7D%7BR%5E2%7D%20%5C%5C%5C%5Cg%20%3D%20%5Cfrac%7BGM%7D%7BR%5E2%7D)
where;
- M is the mass of Earth = 5.972 x 10²⁴ kg
- R is the Radius of Earth = 6,371 km
For Planet Tehar;
![g_T =\frac{G \times 2.1M}{(0.8R)^2} \\\\g_T = 3.28(\frac{GM}{R^2} )\\\\g_T = 3.28 g](https://tex.z-dn.net/?f=g_T%20%3D%5Cfrac%7BG%20%5Ctimes%202.1M%7D%7B%280.8R%29%5E2%7D%20%5C%5C%5C%5Cg_T%20%3D%203.28%28%5Cfrac%7BGM%7D%7BR%5E2%7D%20%29%5C%5C%5C%5Cg_T%20%3D%203.28%20g)
For planet Loput:
![g_L =\frac{G \times 5.6M}{(1.7R)^2} \\\\g_L = 1.94(\frac{GM}{R^2} )\\\\g_L = 1.94g](https://tex.z-dn.net/?f=g_L%20%3D%5Cfrac%7BG%20%5Ctimes%205.6M%7D%7B%281.7R%29%5E2%7D%20%5C%5C%5C%5Cg_L%20%3D%201.94%28%5Cfrac%7BGM%7D%7BR%5E2%7D%20%29%5C%5C%5C%5Cg_L%20%3D%201.94g)
For planet Cremury:
![g_C =\frac{G \times 0.36M}{(0.3R)^2} \\\\g_C = 4(\frac{GM}{R^2} )\\\\g_C = 4 g](https://tex.z-dn.net/?f=g_C%20%3D%5Cfrac%7BG%20%5Ctimes%200.36M%7D%7B%280.3R%29%5E2%7D%20%5C%5C%5C%5Cg_C%20%3D%204%28%5Cfrac%7BGM%7D%7BR%5E2%7D%20%29%5C%5C%5C%5Cg_C%20%3D%204%20g)
For Planet Suven:
![g_s =\frac{G \times 12M}{(2.8R)^2} \\\\g_s = 1.53(\frac{GM}{R^2} )\\\\g_s = 1.53 g](https://tex.z-dn.net/?f=g_s%20%3D%5Cfrac%7BG%20%5Ctimes%2012M%7D%7B%282.8R%29%5E2%7D%20%5C%5C%5C%5Cg_s%20%3D%201.53%28%5Cfrac%7BGM%7D%7BR%5E2%7D%20%29%5C%5C%5C%5Cg_s%20%3D%201.53%20g)
For Planet Pentune;
![g_P =\frac{G \times 8.3 }{(4.1R)^2} \\\\g_P = 0.5(\frac{GM}{R^2} )\\\\g_P = 0.5 g](https://tex.z-dn.net/?f=g_P%20%3D%5Cfrac%7BG%20%5Ctimes%208.3%20%7D%7B%284.1R%29%5E2%7D%20%5C%5C%5C%5Cg_P%20%3D%200.5%28%5Cfrac%7BGM%7D%7BR%5E2%7D%20%29%5C%5C%5C%5Cg_P%20%3D%200.5%20g)
For Planet Rams;
![g_R =\frac{G \times 9.3M}{(4R)^2} \\\\g_R = 0.58(\frac{GM}{R^2} )\\\\g_R = 0.58 g](https://tex.z-dn.net/?f=g_R%20%3D%5Cfrac%7BG%20%5Ctimes%209.3M%7D%7B%284R%29%5E2%7D%20%5C%5C%5C%5Cg_R%20%3D%200.58%28%5Cfrac%7BGM%7D%7BR%5E2%7D%20%29%5C%5C%5C%5Cg_R%20%3D%200.58%20g)
The weight Punch on Each Planet at a constant mass is calculated as follows;
![W = mg\\\\W_T = mg_T\\\\W_T = \frac{236}{g} \times 3.28g = 774.08 \ lb\\\\W_L = \frac{236}{g} \times 1.94g =457.84 \ lb\\\\ W_C = \frac{236}{g}\times 4g = 944 \ lb \\\\ W_S = \frac{236}{g} \times 1.53g = 361.08 \ lb\\\\W_P = \frac{236}{g} \times 0.5 g = 118 \ lb\\\\W_R = \frac{236}{g} \times 0.58 g = 136.88 \ lb](https://tex.z-dn.net/?f=W%20%3D%20mg%5C%5C%5C%5CW_T%20%3D%20mg_T%5C%5C%5C%5CW_T%20%3D%20%5Cfrac%7B236%7D%7Bg%7D%20%5Ctimes%203.28g%20%3D%20774.08%20%5C%20lb%5C%5C%5C%5CW_L%20%3D%20%5Cfrac%7B236%7D%7Bg%7D%20%5Ctimes%201.94g%20%3D457.84%20%5C%20lb%5C%5C%5C%5C%20W_C%20%3D%20%5Cfrac%7B236%7D%7Bg%7D%5Ctimes%204g%20%3D%20944%20%5C%20lb%20%5C%5C%5C%5C%20W_S%20%3D%20%5Cfrac%7B236%7D%7Bg%7D%20%5Ctimes%201.53g%20%3D%20361.08%20%5C%20lb%5C%5C%5C%5CW_P%20%3D%20%5Cfrac%7B236%7D%7Bg%7D%20%5Ctimes%200.5%20g%20%3D%20118%20%5C%20lb%5C%5C%5C%5CW_R%20%3D%20%5Cfrac%7B236%7D%7Bg%7D%20%5Ctimes%200.58%20g%20%3D%20136.88%20%5C%20lb)
Thus, the planet that Punch should travel to in order to weigh 118 lb is Pentune.
<u>The </u><u>complete question</u><u> is below</u>:
Which planet should Punch travel to if his goal is to weigh in at 118 lb? Refer to the table of planetary masses and radii given to determine your answer.
Punch Taut is a down-on-his-luck heavyweight boxer. One day, he steps on the bathroom scale and "weighs in" at 236 lb. Unhappy with his recent bouts, Punch decides to go to a different planet where he would weigh in at 118 lb so that he can compete with the bantamweights who are not allowed to exceed 118 lb. His plan is to travel to Xobing, a newly discovered star with a planetary system. Here is a table listing the planets in that system (<em>find the image attached</em>).
<em>In the table, the mass and the radius of each planet are given in terms of the corresponding properties of the earth. For instance, Tehar has a mass equal to 2.1 earth masses and a radius equal to 0.80 earth radii.</em>
Learn more about effect of gravity on weight here: brainly.com/question/3908593
Answer:
The correct answer is a
Explanation:
At projectile launch speeds are
X axis vₓ = v₀ = cte
Y axis
= v_{oy} –gt
The moment is defined as
p = mv
For the x axis
pₓ = mvₓ = m v₀ₓ
As the speed is constant the moment is constant
For the y axis
p_{y} = m v_{y} = m (v_{oy} –gt) = m v_{oy} - m (gt)
Speed changes over time, so the moment also changes over time
Let's examine the answer
i True
ii False. The moment changes with time
The correct answer is a