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Luda [366]
4 years ago
11

• What are common questions, concerns, practices, and experiences across various world religions? Include indigenous religions i

n your discussion.
Physics
1 answer:
faltersainse [42]4 years ago
5 0

<u>Answer:</u>

<em>They are a lot of religions and faiths across the globe. </em>

<u>Explanation:</u>

There are  a lot of monotheistic and polytheistic religions across the world that took origin at different points in the past.

Some of them are:

  • Christianity- It is a monotheistic religion based on the teachings of Jesus Christ believed to be the son of god.  
  • Confucianism it evolved in China and is based on the teachings scholar and philosopher Confucius. It is a largely secular and humanistic.
  • Buddhism it is based on the life and teachings of Gautama Buddha. Buddhism advocates a way of life with meditation and instructs its followers to be compassionate, kind and wise.  
  • Hinduism –It evolved during the period of Indus valley civilisation and is a polytheistic religion. Hinduism beliefs mention rebirths or ‘punarjanma’.
  • Islam- Islam is a monotheistic religion.It considers Muhammad as the messenger of only god Allah.
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Two pipes of equal length are each open at one end. Each has a fundamental frequency of 470 Hz at 310 K. In one pipe the air tem
Tresset [83]

Answer:

Given:

Fundamental frequency: 470Hz

T1:310k,T2:315k

Calculating velocity

Recall v=(331m/s)✓[T1/273k)

V=331✓(310/273)

V1=331*(1.0656)=352.72m/s

V2=331✓(315/273)=355.5m/s

Fundamental frequency=4L

F2=F1(V2/V1)

F2=470(355.5/352.72)=474.4Hz

Beat=[F2-F1]=474.4-470=4.4Hz

Explanation:

7 0
3 years ago
What factors affect the strength of the electric force between two objects
Nady [450]
There are three factors:

The charge of the two objects. The electric force is proporcional to the product of the charges of both objects.

The distance that separetes them. The electric force is proportional to the inverse of the squared distance that separates the objects.

The media. The electric force constant of proportionality depends on the media: air, water, oil, glass.
5 0
4 years ago
Speedy Sue, que conduce a 30.0 m/s, entra a un túnel de un carril. En seguida observa una camioneta lenta 155 m adelante que se
Romashka [77]

Answer:

Si ocurre una colisión. 5.201 segundos después de que Speedy Sue ingrese al túnel y a una distancia de 128.995 metros.

Explanation:

Supongamos que el vehículo de Speedy Sue decelera a razón constante, mientras que la camioneta se desplaza a velocidad constante. Se requiere conocer si ambos vehículos colisionarán, lo cual implica conocer si existe algún instante tal que ambos tengan la misma posición. Consideremos además que la posición de referencia se encuentra en la posición inicial de Sppedy Sue. Entonces, las ecuaciones cinemáticas son:

Speedy Sue

x_{S} = x_{S,o}+v_{S,o}\cdot t+\frac{1}{2}\cdot a_{S}\cdot t^{2}

Camioneta lenta

x_{C} = x_{C,o} +v_{C}\cdot t

Donde:

x_{S,o}, x_{C,o} - Posiciones iniciales de Speedy Sue y la camioneta lenta, medidas en metros.

v_{S,o} - Velocidad inicial de Speedy Sue, medida en metros por segundo.

v_{S}, v_{C} - Velocidades actuales de Speedy Sue y la camioneta lenta, medidas en metros por segundo.

a_{S} - Deceleración de Speedy Sue, medida en metros por segundo cuadrado.

t - Tiempo, medido en segundos.

Si conocemos que x_{S} = x_{C}, x_{S,o} = 0\,m, x_{C,o} = 155\,m, v_{S,o} = 30\,\frac{m}{s}, v_{C} =-5\,\frac{m}{s} y a_{S} = -2\,\frac{m}{s^{2}}, encontramos la siguiente función cuadrática:

155\,m + \left(-5\,\frac{m}{s} \right)\cdot t = 0\,m+\left(30\,\frac{m}{s} \right)\cdot t +\frac{1}{2}\cdot (-2\,\frac{m}{s^{2}} )\cdot t^{2}

-t^{2}+35\cdot t-155 = 0 (Ec. 1)

Las raíces de esta función son:

t_{1}\approx 29.798\,s, t_{2} \approx 5.201\,s

La colisión ocurriría en la raíz positiva más pequeña, es decir:

t \approx 5.201\,s

Ahora, la posición en que ocurriría la colisión se determina a partir de la ecuación de desplazamiento de la camioneta lenta, es decir: (v_{C,o} = -5\,\frac{m}{s},  x_{C,o} = 155\,m, t \approx 5.201\,s)

x_{C} = 155\,m +\left(-5\,\frac{m}{s}\right)\cdot (5.201\,s)

x_{C} = 128.995\,m

En síntesis, si ocurre una colisión. 5.201 segundos después de que Speedy Sue ingrese al túnel y a una distancia de 128.995 metros.

0 0
3 years ago
Use the data provided to calculate the gravitational potential energy of each cylinder mass. Round your answers to the nearest t
pantera1 [17]

Answer: 3kg: 14.7 6kg: 29.4 9kg: 44.1

Explanation: just did it on Edge

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3 years ago
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An astronaut is in equilibrium when he is positioned 140 km from the center of asteroid X and 481 km from the center of asteroid
mariarad [96]

Explanation:

It is given that, An astronaut is in equilibrium when he is positioned 140 km from the center of asteroid X and 481 km from the center of asteroid Y, along the straight line joining the centers of the asteroids. We need to find the ratio of their masses.

As they are in equilibrium, the force of gravity due to each other is same. So,

\dfrac{Gm_xM}{r^2}=\dfrac{Gm_yM}{r^2}\\\\\dfrac{m_x}{r_x^2}=\dfrac{m_y}{r_y^2}\\\\\dfrac{m_x}{r_x^2}=\dfrac{m_y}{r_y^2}\\\\\dfrac{m_x}{m_y}=(\dfrac{r_x^2}{r_y^2})\\\\\dfrac{m_x}{m_y}=(\dfrac{140^2}{481^2})\\\\\dfrac{m_x}{m_y}=0.0847

So, the ratio of masses X/Y is 0.0847

5 0
3 years ago
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