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tamaranim1 [39]
3 years ago
12

A person is jumping...

Physics
1 answer:
Marizza181 [45]3 years ago
5 0
And gets themselves seriously injured or fell on someone else
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Two critical requirements must be met before light elements, like hydrogen or helium, will fuse and form heavier elements. the t
sattari [20]
In order to achieve a nuclear fusion, one of the following requirements that must be attained are high temperature and high pressure.

High temperature - temperature must be 100 million degrees kelvin to a point that hydrogen already becomes plasma

High pressure - extremely high pressure is required so that the distance between hydrogen atoms must be at the required 1 picometer apart
7 0
4 years ago
2.According to Newton’s first law, if no force acts on an object, it will just continue moving. Explain in terms of Newton’s fir
xxMikexx [17]
The answer

<span>According to Newton’s first law, if no force acts on an object, it will just continue moving in a straight line with a constant speed or at rest
that means that the sum of all acting forces equals 0

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exert a force between the car and the road to drive at a constant speed on a straight and level road because the both forces must be balances for making it to move <span><span>with a constant speed in a straight line.</span> </span>


6 0
3 years ago
A car is driving at 85 km/h and the driver spots a stop sign ahead. What coefficient of friction is needed to stop the car at th
almond37 [142]

Answer:

μ = 0.0315

Explanation:

Since the car moves on a horizontal surface, if we sum forces equal to zero on the Y-axis, we can determine the value of the normal force exerted by the ground on the vehicle. This force is equal to the weight of the cart (product of its mass by gravity)

N = m*g (1)

The friction force is equal to the product of the normal force by the coefficient of friction.

F = μ*N (2)

This way replacing 1 in 2, we have:

F = μ*m*g (2)

Using the theorem of work and energy, which tells us that the sum of the potential and kinetic energies and the work done on a body is equal to the final kinetic energy of the body. We can determine an equation that relates the frictional force to the initial speed of the carriage, so we will determine the coefficient of friction.

\frac{1}{2} *m*v_{i}^{2}-(F*d)=  \frac{1}{2} *m*v_{f}^{2}

where:

vf = final velocity = 0

vi = initial velocity = 85 [km/h] = 23.61 [m/s]

d = displacement = 900 [m]

F = friction force [N]

The final velocity is zero since when the vehicle has traveled 900 meters its velocity is zero.

Now replacing:

(1/2)*m*(23.61)^2 = μ*m*g*d

0.5*(23.61)^2 = μ*9,81*900

μ = 0.0315

5 0
3 years ago
A mass hanged on a spring scale. what is the force exerted by gravity on 700g ?
Ipatiy [6.2K]

Answer:

6.86 N

Explanation:

Applying,

F = mg............... Equation 1

Where F = Force exerted by gravity on the mass, m = mass, g = acceleration due to gravity

Note: The Force exerted by gravity on the mass is thesame as the weight of the body.

From the question,

Given: m = 700 g = (700/1000) = 0.7 kg

Constant: g = 9.8 m/s²

Substitute these values into equation 1

F = 9.8(0.7)

F = 6.86 N

6 0
3 years ago
A coin is placed 29 cm from the center of a horizontal turntable, initially at rest. The turntable then begins to rotate. When t
kobusy [5.1K]

Answer:

The coefficient of static friction between the coin and the turntable is 0.51

Explanation:

at the time of the slip:

centripetal force = frictional force

mv^2/r = x*m*980

v^2/r = 980x

x = v^2/980r

  = [(120)^2]/[980*29]

  = 0.51

Therefore, The coefficient of static friction between the coin and the turntable is 0.51

5 0
3 years ago
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