Answer:
<h2>Three laws of motion haha.....</h2>
The answer is 570 J. The kinetic energy has the formula of 1/2mV². The total work in this process W= 1/2m(V2²-V1²) = 1/2 * 15.0 * (11.5²-7.50²) = 570 J.
answer
64 is C (c) 1-Bromo-3-methylbutane
63 is D
i is secondary ii is primary