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Gala2k [10]
3 years ago
14

A car of mass 1000 kg travels around a level curve of radius 40 m. If the maximum frictional force that can be exerted upon the

car by the road (determined by the coefficient of friction between the tires and the road) is 7000 N how fast can the car travel without "spinning out?"
Physics
1 answer:
Tasya [4]3 years ago
8 0

Answer:

The car can travel V=19.8m/s without spinning out

Explanation:

Given that

Mass of the car m=1000kg

Radius of curve r =40m

frictional force R=7000N

Coefficient of friction u=?

We know that F=uR

But F=ma

F=1000*9.81

F=9810N

Therefore u=F/R

u=9810/7000

u=1.40

For the car to travel without spinning out we

Equate it centripetal force formula to frictional force formula

F=mv²/r

F=ur

hence mv²/r=uR

Making velocity subject of formula we have v²=u*r*R/m

V²=(1.4*40*7000)/1000

V²=392

V=√ 392

V=19.8m/s

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An electric toaster is rated 1200 watts at 120 volts. what is the total electrical energy used to operate the toaster for 30 sec
Tresset [83]

Answer : Total electrical energy is 36000 J.

Explanation :

It is given that,

Power of electric toaster, P = 1200 Watts

Voltage, V = 120 Volts

Time, t = 30 s

Electric energy is defined as the product of the power and the time taken.

E=Pt

E=1200\ W\times 30\ s

E=36000\ J

Total electrical energy used to operate the toaster for 30 seconds is 36000 J.

8 0
4 years ago
Read 2 more answers
A hydraulic system at the mechanic shop can perform up to 180,000 joules of work in a day. if throughout the day it can lift 10
snow_tiger [21]

Answer:

9,000 N.

Explanation:

Workdone can be defined as the ability to do work. It is also the product of the force and the distance it is being moved.

Mathematically,

W = F * d

= 180,000/2

= 90,000 N.

Weight of the 10 cars = 90,000 N.

Weight of a car = 90000/10

= 9,000N.

5 0
4 years ago
The light reactions could be viewed as analogous to a hydro-electric dam. In that case, the wall of the dam that holds back the
Viktor [21]

The light reactions could be viewed as analogous to a hydroelectric dam. In that case, the wall of the dam that holds back the water would be analogous to the thylakoid membrane.

Thylakoid membrane is present in cyanobacteria and chloroplasts of plants. It plays a crucial role in photosynthesis and photosystem II reactions.

In general, these are the regions where light-dependent reactions take place. The thylakoid membrane is a lipid-bound membrane that maintains potential difference and also controls the flow of liquids across the membrane during light reactions.

In the provided case, we can see that the wall of the dam holds back the water, similarly, in light-dependent reactions, thylakoid membranes control the liquid flow and also regulate the potential gradient across the membrane and also allow the selective proteins to pass through.

If you need to learn more about light reactions click here:

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3 0
2 years ago
A 620 kg moose is standing in the middle of a train track. A 10,000 kg train moving at 10 m/s is unable to stop and the moose en
ddd [48]

Answer:

This is an example of Inelastic colission

Explanation:

Step one:

given:

mass of moose m1 = 620 kg

mass of train m2= 10,000kg

Initial velocity of moose  u1= 0 m/s

Initial velocity of train v1 = 10m/s

combined velocity of the system is given as v

Applying the conservation of momentum equation we have

m1u1+ m2u1= (m1+m2)V

substitutting we have

620*0+10000*10= (620+10000)V

100000= 10620V

divide both sides by 10620

V = 100000/10620

V=9.41m/s

The velocity of the moose after impact is 9.41m/s

4 0
3 years ago
The force of gravity considers which two parts?
attashe74 [19]
Mass of object/source
Gravity
Fg=mg
3 0
3 years ago
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