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guajiro [1.7K]
3 years ago
13

How does the state of atoms in a neon light change when light is emitted?

Chemistry
2 answers:
barxatty [35]3 years ago
7 0
How does the state of atoms in a neon light change when light is emitted? They lose energy.-I hope this is correct!
Link: https://quizlet.com/4708128/chapter-4-flash-cards/


Blababa [14]3 years ago
5 0
The state of atoms in a neon light when light is emitted is loss of energy.
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An automated filling machine is used to fill bottles with liquid detergent. A random sample of 20 bottles results in a sample va
taurus [48]

Answer:

No, there is no evidence that the manufacturer has a problem with underfilled or overfilled bottles, due that according our results we cannot reject the null hypothesis.

Explanation:

according to this exercise we have the following:

σ^2 =< 0.01 (null hypothesis)

σ^2 > 0.01 (alternative hypothesis)

To solve we can use the chi-square statistical test. To reject or not the hypothesis, we have that the rejection region X^2 > 30.14

Thus:

X^2 = ((n-1) * s^2)/σ^2 = ((20-1)*0.0153)/0.01 = 29.1

Since 29.1 < 30.14, we cannot reject the null hypothesis.

4 0
3 years ago
Read 2 more answers
Would a false positive from the reaction between the inoculating loop and hydrogen peroxide
Svetradugi [14.3K]
The false positive from the response of hydrogen peroxide and the immunizing circle would be created by poor specificity. The recipe for specificity is TN/TN+FP. False-positive outcomes can be ascribed to meddling substances in nature where the strips are put away or utilized, for example, hydrogen peroxide (H2O2) or fade (hypochlorite).
3 0
3 years ago
How many liters of water must be added to 0.291 g of NaCl to create a salt water solution that has a concentration of 2.41 g/L?
dmitriy555 [2]
C=2.41 g/L
m(NaCl)=0.291 g

c=m(NaCl)/v

v=m(NaCl)/c

v=0.291/2.41= 0.1207 L = 120.7 mL
4 0
3 years ago
Read 2 more answers
What is flame emission spectroscopy
zmey [24]
Flame emission is a method of chemical that uses intensity of light from a flame.
3 0
3 years ago
A 4.3 L gas bubble at STP is heated to 984 K, and the pressure increases to 1520 mmHg. What is the new volume?
Natalka [10]

Answer:

v2=40.35L

Explanation:

p1v1/t1=p2v2/t2

v2=t2p1v1/t1p2

v2=984*760*22.4/273.15*1520

v2=40.35 L

5 0
2 years ago
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