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guajiro [1.7K]
2 years ago
13

How does the state of atoms in a neon light change when light is emitted?

Chemistry
2 answers:
barxatty [35]2 years ago
7 0
How does the state of atoms in a neon light change when light is emitted? They lose energy.-I hope this is correct!
Link: https://quizlet.com/4708128/chapter-4-flash-cards/


Blababa [14]2 years ago
5 0
The state of atoms in a neon light when light is emitted is loss of energy.
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When a sample of rust was mixed with acid, the rust changed into two simpler substances: W and Z. The substances W and Z could n
julia-pushkina [17]

here can be a number of chemical processes by which a compounds can be broken down into simpler substances. The most common and wide-spread of such processes is Catabolism. Along with anabolism, catabolism make up the metabolism process for living organisms. In catabolism, complex chemical molecules (such as proteins, polysaccharides, etc.) are broken down into simpler molecules (such as amino acids, monosaccharides, etc.). This is often accompanied by release of energy in the form of ATP (adenosine triphosphate) molecules and intermediate metabolites (which can be used by the organism in the anabolic processes). The energy thus generated is used for operation and maintenance of cells (and consequently, the body).  

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Hope this helps.

6 0
3 years ago
Read 2 more answers
A metal sample has a mass of 64.2 g. What is the density of this metal?
brilliants [131]

density= mass/volume

we need the volume of the metal to find the density,  in which case the answer would be 64.2/volume=density

8 0
3 years ago
Need asap thank you
cupoosta [38]

Answer:

c.boron-11

Explanation:

The atomic mass of boron is 10.81 u.

And 10.81 u is a lot closer to 11u than it is to 10u, so there must be more of boron-11.

To convince you fully, we can also do a simple calculation to find the exact proportion of boron-11 using the following formula:

(10u)(x)+(11u)(1−x)100%=10.81u

Where u is the unit for atomic mass and x is the proportion of boron-10 out of the total boron abundance which is 100%.

Solving for x we get:

11u−ux=10.81u

0.19u=ux

x=0.19

1−x=0.81

And thus the abundance of boron-11 is roughly 81%.

6 0
2 years ago
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Charra [1.4K]

Answer:

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Explanation:

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2 years ago
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Elanso [62]
B 18 is the answer ......
7 0
2 years ago
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