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Sveta_85 [38]
3 years ago
12

Balance the following equation. C3H8(g) + O2(g) → CO2(g) + H2O(l)

Chemistry
1 answer:
Arte-miy333 [17]3 years ago
8 0

Explanation:

C3H8+5O2----->3CO2+4H2O

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What did Dalton's atomic theory contribute to science?
Serga [27]

Answer:

B

Explanation:

Pasted below is his 5 theory's and all of them are the building blocks of chemistry today.  

1. Matter is made up of atoms that are indivisible and indestructible.

2. All atoms of an element are identical.

3. Atoms of different elements have different weights and different chemical properties.

4. Atoms of different elements combine in simple whole numbers to form compounds.

5. Atoms cannot be created or destroyed. When a compound decomposes, the atoms are recovered unchanged.

4 0
3 years ago
When liquid water evaporates to gaseous water
alina1380 [7]

Answer: liquid water 2

Explanation:

5 0
3 years ago
What is a substance's specific heat? the energy required to raise one kilogram of the substance one degree the energy required t
rodikova [14]

the energy required to raise one kilogram of the substance one degree

4 0
3 years ago
2. Incoming wastewater, with BOD5 equal to 200 mg/L, is treated in a well-run secondary treatment plant that removes 90 percent
Lesechka [4]

Answer:

10.8 ml

Explanation:

The BOD is an empirical test to determine the molecular oxygen used during a specified incubation period (usually five days), for the biochemical degradation of organic matter (carbonaceous demand) and the oxygen used to oxidise inorganic matter.

See attached file

5 0
3 years ago
If is found that 24.68 mL of .1165 M NaOH is needed to titrate .2931 g of an unknown acid to the phenolphthalein end point. Calc
Lemur [1.5K]

Answer: The equivalent mass of the acid is 83.16 grams

Explanation:

To calculate the number of moles for given molarity, we use the equation:

\text{Moles of solute}={\text{Molarity of the solution}}\times{\text{Volume of solution (in L)}}  

Molarity of NaOH solution = 0.1165 M

Volume of NaOH solution = 24.68 mL = 0.02468 L

Putting values in equation 1, we get:

\text{Moles of} NaOH={0.1165M}\times{0.02468L}=2.875\times 10^{-3}moles=2.875\times 10^{-3}geq    

( as acidity of NaOH is 1)

For end point:  gram equivalents of acid =  gram equivalents of base = 2.875\times 10^{-3}

Mass of acid=gram equivalents\times {\text {Equivalent mass}}

0.2391=2.875\times 10^{-3}\times {\text {Equivalent mass}}

{\text {Equivalent mass}}=83.16g

Thus equivalent mass of the acid is 83.16 grams

5 0
3 years ago
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