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3 years ago

I need help with this question

Chemistry

1 answer:

Leviafan [203]3 years ago

3 0

Answer:

i do not know the answer but pls give a heart and five starts so i can ask questions pls

Explanation:

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When copper(II) oxide is heated with hydrogen gas, water and copper metal is produced. What mass of copper can be obtained if 32

Vadim26 [7]

Answer:

25.5 g

Explanation:

First, you will need a balanced chemical equation

CuO + H₂ ==> H₂O + Cu

From the equation above, we can see that for every 1 mole of CuO (copper(II) oxide), 1 mole of Cu (copper) is produced.

Convert grams of CuO to moles. You should get 0.402 mol. Now with the relationship established above, you can see that you should ideally get 0.402 mol. Convert this to grams. Your answer should be 25.5 g.

8 0

3 years ago

A buffer with a pH of 4.31 contains 0.31 M of sodium benzoate and 0.24 M of benzoic acid. What is the concentration of [ H 3 O ]

Mnenie [13.5K]

Answer: The hydronium ion concentration in the solution is $1.29\times 10^{-4}M$

Explanation:

To calculate the molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Moles hydrochloric acid solution = 0.060 mol

Volume of solution = 1 L

Putting values in above equation, we get:

$\text{Molarity of HCl}=\frac{0.060}{1L}\\\\\text{Molarity of HCl}=0.060M$

The chemical reaction for aniline and HCl follows the equation:

$C_6H_5COO^-+HCl\rightarrow C_6H_5COOH+Cl^-$

Initial: 0.24 0.060 0.31

Final: 0.18 - 0.37

To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:

$pH=pK_a+\log(\frac{[\text{conjugate acid}]}{[\text{base}]})$

$pH=pK_a+\log(\frac{[C_6H_5COO^-]}{[C_6H_5COOH]})$

We are given:

$pK_a$ = negative logarithm of acid dissociation constant of benzoic acid = 4.2

$[C_6H_5COO^-]=0.18M$

$[C_6H_5COOH]=0.37M$

pH = ?

Putting values in equation 1, we get:

$pH=4.2+\log(\frac{0.18}{0.37})\\\\pH=3.89$

To calculate the hydronium ion concentration in the solution, we use the equation:

$pH=-\log[H_3O^+]$

pH = 3.89

Putting values in above equation, we get:

$3.89=-\log[H_3O^+]$

$[H_3O^+]=10^{-3.89}=1.29\times 10^{-4}M$

Hence, the hydronium ion concentration in the solution is $1.29\times 10^{-4}M$

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3 years ago

Which of the following accurately describes semiconductor diodes? A. Unlike junction diodes, point-contact diodes are enclosed i

Anna007 [38]

The correct answer is letter A: Unlike junction diodes, point-contact diodes are enclosed in a suitable casing and have terminals for connecting them to a circuit.

5 0

4 years ago

Read 2 more answers

Who can help me with a few chemistry balancing equtions?

hoa [83]

Who can help me with a few chemistry balancing equations?
Me. Just show me the equations :)

6 0

3 years ago

Which of following affects liquifaction of gases except

iogann1982 [59]

Answer:

pressure

Explanation:

gas convert to liquid at high pressure.

4 0

3 years ago