Answer:
The day I was in the shower and I will be there at remove the day I was in the shower and I will be there at remove the day to see if you have any questions please feel free to contacts and the day I was in the shower and I will be there at remove the day I was in the shower and I will be there at remove the days of the week are you
Answer:
92gm
Explanation:
Atomic mass of Mg=24g=1 mole of Mg
∴ 24g =1 mole of Mg contain 6.022×10^23 atom
∴ 6gm contains 246.022×1023×6
=4×6.022×10^23 atoms
Now according to question, there are 6.022×1023 atoms of Na
23gm of Na contains 6.022×10^23 atoms
∴6.022×4×10^23 atoms of Na weighs 23×6.022×10^23×4/6.022×10^23⇒92gm
Answer:
0.289J of heat are added
Explanation:
We can relate the change in heat of a substance with its increasing in temperature using the equation:
q = m*ΔT*S
<em>Where Q is change in heat</em>
<em>m is mass of substance (In this case, 0.0948g of water)</em>
<em>ΔT = 0.728°C</em>
<em>S is specific heat (For water, 4.184J/g°C)</em>
Replacing:
q = 0.0948g*0.728°C*4.184J/g°C
q = 0.289J of heat are added
Answer:
1. 10.37114 psi
2. 71.5178 KPa
3. 71517.8 Pa
4. 536.56 mmHg.
5. 21.12352 inHg
Explanation:
From the question given,
Pressure = 0.706 atm
The pressure in other units of measurement is obtained as follow:
1. Pressure in Psi
1 atm = 14.69 psi
Therefore, 0.706 atm = 0.706 x 14.69 = 10.37 psi
2. Pressure in KPa
1 atm = 101.3 kPa
Therefore, 0.706 atm = 0.706 x 101.3 = 71.5178 KPa
3. Pressure in Pa
1 atm = 1.013x10^5 Pa
Therefore, 0.706 atm = 0.706 x 1.013x10^5 = 71517.8 Pa
4. Pressure in mmHg
1 atm = 760mmHg
Therefore, 0.706 atm = 0.706 x 760 = 536.56 mmHg
5. Pressure in inHg
1 atm = 29.92 inHg
Therefore, 0.706 atm = 0.706 x 29.92 = 21.12352 inHg
Answer:
6,216.684 kilograms of sodium carbonate must be added to neutralize 
of sulfuric acid solution.
Explanation:
Mass of sulfuric acid solution = 
Percentage mass of sulfuric acid = 95.0%
Mass of sulfuric acid = 
Moles of sulfuric acid = 
According to reaction , 1 mole of sulfuric acid is neutralized by 1 mole of sodium carbonate.
Then 58,647.96 moles of sulfuric acisd will be neutralized by :
of sodium carbonate
Mass of 58,647.96 moles of sodium carbonate :
6,216,683.76 g = 6,216,683.76 × 0.001 kg = 6,216.684 kg
6,216.684 kilograms of sodium carbonate must be added to neutralize of sulfuric acid solution.
