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andrezito [222]
3 years ago
15

A. Energy is transferred to different forms

Chemistry
1 answer:
Luden [163]3 years ago
3 0

Answer:

A. Energy is transferred to different forms .

Explanation:

Hello!

In this case, we need to consider the law of conservation of mass and energy which states that mass and energy cannot be neither created nor destroyed, just modified; it means we can rule out B. and C. so far.

Moreover, since D. is actually true for combustion reactions because they are used to provide energy in industrial operations, this is not the concern here because a combustion reaction is not considered.

Therefore the correct option is A. Energy is transferred to different forms as the energy provided by Rose is transferred to the pendulum system .

Best regards!

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A solution of permanganate is standardized by titration with oxalic acid, . To react completely with mol of oxalic acid required
Zielflug [23.3K]

Answer:

M=0.120M

Explanation:

Hello,

In this case, the undergone chemical reaction is:

MnO_4^-(aq)+H_2C_2O_4(aq)\rightarrow Mn^{+2}+CO_2

In such a way, the acidic redox balance turns out:

(Mn^{+7}O_4)^-+5e^-+8H^+\rightarrow Mn^{+2}+4H_2O\\H_2C_2O_4\rightarrow2CO_2+2H^++2e^-

Which leads to the total balanced equation as follows:

2(MnO_4)^-(aq)+6H^+(aq)+5H_2C_2O_4(aq)\rightarrow2Mn^{+2}(aq)+8H_2O(l)+10CO_2(g)

Thus, as the mass of oxalic acid is not given, one could suppose a value of 1 g (which you can modify based on the actual statement) in order to compute the oxalic acid moles as shwon below:

1gH_2C_2O_4*\frac{1molH_2C_2O_4}{90.04gH_2C_2O_4} *\frac{2mol(MnO_4)^-}{5molH_2C_2O_4} =0.00444mol(MnO_4)^-

Whereby the molality results:

M=\frac{0.00444mol(MnO_4)^-}{0.03702L} =0.120M

Remember you can modify the oxalic acid mass as you desire.

Best regards.

5 0
3 years ago
In which type of condition is a conditions is a landslide most likely to occur
masha68 [24]

Answer:

<u>B. In a wet, hilly area</u>

Explanation:

We know that for a landslide to happen, there has to be a down hill slope so it can fall.

This eliminates answers C, D and E.

So we are left with A and B

Now we can look at this in a real life scenario. If you have ever walking on wet ground, you will know that is weaker than dry ground. Knowing this, we know the answer will have to be answer B.

6 0
3 years ago
43.2 + 50.0 + 16.0= answer in correct amount of significant figures
Molodets [167]

Answer : The correct answer is 109.

Explanation :

Significant figure : It is defined as the each digits of a number have meaning or contribute to the value of the number.

The addition of given digits is,

43.2 + 50.0 + 16.0 = 109.2

As per the question, the given digits has 3 significant figures. But the answer after addition is 109.2 has 4 significant figures.

The addition rule of significant rule is the least precise number of significant figure in any number of the problem determines the number of significant figures in the answer.

Therefore, from the addition rule, the correct answer is 109.

4 0
3 years ago
What is the General equation of combustion
sdas [7]
Combustion<span> Reactions, a </span>combustion<span> reaction always has oxygen as one reactant. The second reactant is always a hydrocarbon, which is a compound made up of carbon and hydrogen. A</span>combustion<span> reaction also always produces such as C02 and H20</span>
7 0
3 years ago
From the enthalpies of reaction H2(g)+F2(g)→2HF(g)ΔH=−537kJ C(s)+2F2(g)→CF4(g)ΔH=−680kJ 2C(s)+2H2(g)→C2H4(g)ΔH=+52.3kJ calculate
DIA [1.3K]

Answer:

\Delta H for the given reaction is -2486.3 kJ

Explanation:

The given equation can be written as a combination of the following equation:

2H_{2}(g)+2F_{2}(g)\rightarrow 4HF(g)  ; \Delta H_{1}= (2\times -537kJ)=-1074 kJ

2C(s)+4F_{2}(g)\rightarrow 2CF_{4}(g)  ;  \Delta H_{2}=(2\times -680kJ)=-1360kJ

C_{2}H_{4}(g)\rightarrow 2C(s)+2H_{2}(g)  ;  \Delta H_{3}=-52.3kJ

-----------------------------------------------------------------------------------

C_{2}H_{4}(g)+6F_{2}(g)\rightarrow 2CF_{4}(g)+4HF(g)

\Delta H=\Delta H_{1}+\Delta H_{2}+\Delta H_{3}=(-1074-1360-52.3)kJ=-2486.3kJ

6 0
3 years ago
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