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3 years ago

If two identical objects are dropped one after 1 s delay with respect to another then in the absence of the air resistance *

Physics

1 answer:

zloy xaker [14]3 years ago

5 0

Answer:

A.No. Assuming no other factors (such as air resistance) the first object will have a velocity of 32 feet/second when the other is dropped. Since they will both have the same acceleration, the first distance between them will increase by 32 feet per second.

Explanation:

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Is it safe to drive your 1600-kg car at speed 34 m/s around a level highway curve of radius 190 m if the effective coefficient o

adoni [48]

Answer:

It is unsafe

Explanation:

v = Velocity of car = 34 m/s

r = Radius of turn = 190 m

$\mu$ = Coefficient of static friction = 0.5

m = Mass of car = 1600 kg

g = Acceleration due to gravity = 9.81 m/s²

The centripetal force is given by

$F_c=m\frac{v^2}{r}\\\Rightarrow F_c=1600\frac{34^2}{190}\\\Rightarrow F_c=9734.73\ N$

The frictional force is given by

$F_f=\mu mg\\\Rightarrow F_f=0.5\times 1600\times 9.81\\\Rightarrow F_f=7848\ N$

If the centripetal force is greater than the frictional force then the car will slip which makes it unsafe.

Here, the centripetal force is greater than the frictional force which makes it unsafe to drive it at that speed.

4 0

3 years ago

Which phrases apply to the formation of the Grand Canyon?

Damm [24]

Answer:

Large scale

Explanation:

short term

6 0

3 years ago

1 2 3 4 5 6 7 8 9 10

7nadin3 [17]

Answer:

<h2>C. 0.55 m/s towards the right</h2>

Explanation:

Using the conservation of law of momentum which states that the sum of momentum of bodies before collision is equal to the sum of the bodies after collision.

Momentum = Mass (M) * Velocity(V)

BEFORE COLLISION

Momentum of 0.25kg body moving at 1.0m/s = 0.25*1 = 0.25kgm/s

Momentum of 0.15kg body moving at 0.0m/s(body at rest) = 0kgm/s

AFTER COLLISION

Momentum of 0.25kg body moving at x m/s = 0.25* x= 0.25x kgm/s

x is the final velocity of the 0.25kg ball

Momentum of 0.15kg body moving at 0.75m/s(body at rest) =

0.15 * 0.75kgm/s = 0.1125 kgm/s

Using the law of conservation of momentum;

0.25+0 = 0.25x + 0.1125

0.25x = 0.25-0.1125

0.25x = 0.1375

x = 0.1375/0.25

x = 0.55m/s

Since the 0.15 kg ball moves off to the right after collision, the 0.25 kg ball will move at 0.55 m/s towards the right

4 0

3 years ago

Which one isnt a part of he respiratory system?

Vsevolod [243]

Answer:

Colon isn't a part of respiratory system

8 0

3 years ago

The primary 40-turn coil of an ideal transformer is supplied with 120 V (rms). If the rms voltage output of the secondary coil i

Svet_ta [14]

Answer:

No. of turns in secondary coil are 5.

Transformer Type: STEP DOWN TRANSFORMER

Explanation:

The relationship of the no. of turns in transformer secondary and primary coils with their voltages is known as the turn ration. The formula for turns ratio is as follows:

Np/Ns = Vp/Vs

where,

Np = No. of turns in primary coil = 40

Ns = No. of turns in secondary coil = ?

Vp = Voltage supplied to primary coil = 120 V

Vs = Voltage output of secondary coil = 15 V

Therefore,

40/Ns = 120 V/15 V

Ns = 40/8

Ns = 5

TYPE OF TRANSFORMER:

Since, this transformer decreases the voltage value at the output. Hence it is a STEP DOWN TRANSFORMER.

7 0

4 years ago