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katovenus [111]
3 years ago
5

You fire a paintball from a paintball gun straight up into the air at 25.0 m/s. What is the ball velocity at the higher point th

at the ball reaches? Pleaseee helppp mee
Physics
1 answer:
iVinArrow [24]3 years ago
5 0

Given :

You fire a paintball from a paintball gun straight up into the air at 25.0 m/s.

To Find :

What is the ball velocity at the higher point that the ball reaches.

Solution :

We know, when ball is moving upward acceleration due to gravity is applied downward.

So, the ball will decelerate and when ball reaches maximum height its velocity will become zero.

Therefore, ball velocity is 0 m/s at maximum height.

Hence, this is the required solution.

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hichkok12 [17]
I'm not sure, but I'm pretty sure it depends.
7 0
3 years ago
A force of 660 n stretches a certain spring a distance of 0.300 m. what is the potential energy of the spring when a 70.0 kg mas
kkurt [141]
A force of 660 n stretches a certain spring a distance of 0.300 m. what is the potential energy of the spring when a 70.0 kg mass hangs vertically from it?
5 0
4 years ago
PLEASE I NEED HELP I AM REALLY STUCK!!!
AlekseyPX

Answer: Force = Mass X Acceleration

F = 5 x 2

F = 10 N

8 0
3 years ago
A remote-controlled car's wheel accelerates at 22.6 rad/s2 . If the wheel begins with an angular speed of 10.2 rad/s, what is th
Lapatulllka [165]

Answer:

70.9pi rad/s

Explanation:

angle turned through = 16

angular acceleration = 22.6 rad/s2

angular speed = 10.2 rad/s

time = ?

angular acceleration = angular speed/time

time = 10.2/22.6

time = <u>0</u><u>.</u><u>4</u><u>5</u><u> </u><u>s</u><u>e</u><u>c</u><u>o</u><u>n</u><u>d</u><u>s</u>

<u>angular speed</u><u> </u><u>=</u><u> </u><u>a</u><u>n</u><u>g</u><u>l</u><u>e</u><u> </u><u>t</u><u>u</u><u>r</u><u>n</u><u>e</u><u>d</u><u> </u><u>t</u><u>h</u><u>r</u><u>o</u><u>u</u><u>g</u><u>h</u><u>/</u><u>t</u><u>i</u><u>m</u><u>e</u>

<u>angular speed</u><u> </u><u>=</u> (16 × 2pi)/0.45

= 70.9pi rad/s

3 0
3 years ago
Chapter 38, Problem 001
Norma-Jean [14]

Answer:

a) \lambda=2.95x10^{-6}m

b) infrared region

Explanation:

Photon energy is the "energy carried by a single photon. This amount of energy is directly proportional to the photon's electromagnetic frequency and is inversely proportional to the wavelength. If we have higher the photon's frequency then we have higher its energy. Equivalently, with longer the photon's wavelength, we have lower energy".

Part a

Is provide that the smallest amount of energy that is needed to dissociate a molecule of a material on this case 0.42eV. We know that the energy of the photon is equal to:

E=hf

Where h is the Planck's Constant. By the other hand the know that c=f\lambda and if we solve for f we have:

f=\frac{c}{\lambda}

If we replace the last equation into the E formula we got:

E=h\frac{c}{\lambda}

And if we solve for \lambda we got:

\lambda =\frac{hc}{E}

Using the value of the constant h=4.136x10^{-15} eVs we have this:

\lambda=\frac{4.136x10^{15}eVs (3x10^8 \frac{m}{s})}{0.42eV}=2.95x10^{-6}m

\lambda=2.95x10^{-6}m

Part b

If we see the figure attached, with the red arrow, the value for the wavelenght obtained from part a) is on the infrared region, since is in the order of 10^{-6}m

4 0
3 years ago
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