The balanced chemical equation for the given reaction:
NaHCO₃ + HCl --> NaCl + H₂O + CO₂
Given, mass of NaHCO₃ = 0.05 g
Molar mass of NaHCO₃ = 84.007 g/mol
Moles = mass/molar mass
Moles of NaHCO₃ = 0.05 g/84.007 g/mol
Moles of NaHCO₃ = 6.0 x 10⁻⁴
Given, mass of HCl = 0.05 g
Molar mass of HCl = 36.46 g/mol
Moles of HCl = 0.05 g/ 36.46 g/mol
Moles of HCl = 1.4 x 10⁻³
Since NaHCO3 has the least number of moles, it is the limiting reagent.
As per the balanced equation the molar ratio between NaHCO₃ : CO₂ is 1:1
Therefore, moles of CO₂ = 6.0 x 10⁻⁴
Molar mass of CO₂ = 44 g/mol
Mass = moles x molar mass
Mass of CO₂ = 6.0 x 10⁻⁴ mol x 44 g/mol = 0.0264 g
Mass of carbon dioxide gas produced = 0.0264 g
