All categories

3 years ago

What is a combination of symbols that shows the ratio of elements in a compound

1 answer:

8 0

The combination of symbols that shows the ratio of elements in a compound is called chemical formula. A chemical formula is one of the ways in expressing information about the ratio and proportion of atoms that consists a particular chemical compound. This is done by using a single line pf chemical symbols of elements, numbers, and sometimes parentheses, comma, dashes, brackets and sometimes the positive and negative sign. Chemical formula can completely specify the simplest structure of molecules and chemical substances.

You might be interested in

What makes the ball stop on rolling after somtime

Gnoma [55]

A ball stops because the surface on which it rolls resists its motion. So the ball stops because of friction.

3 0

3 years ago

Read 2 more answers

What kinds of bonds can happen between the elements of a compound

Anit [1.1K]

What kinds of bonds can happen between the elements of a compound?

Covalent and Ionic

4 0

3 years ago

Please HELP!!!!!!!!!!!!

Lunna [17]

Answer:

If it served you, give me 5 stars please, thank you!

Muzzle velocity 300 m/s corresponds to the .38 special

Thus, the shooter is Janice Jackson with .38 special.

5 0

3 years ago

A solenoid inductor has an emf of 0.80 V when the current through it changes at the rate 10.0 A/s. A steady current of 0.20 A pr

barxatty [35]

Answer:

The number of turns of the inductor is 2000 turns.

Explanation:

Given;

emf of the inductor, E = 0.8 V

the rate of change of current with time, dI/dt = 10 A/s

steady current in the solenoid, I = 0.2 A

flux per turn, Ф = 8.0 μWb per

Determine the inductance of the solenoid, L

E = L(dI/dt)

L = E / (dI/dt)

L = 0.8 / (10)

L = 0.08 H

The inductance of the solenoid is given by;

$L = \frac{\mu_o N^2 A}{l}$

Also, the magnetic field of the solenoid is given by;

$B = \frac{\mu_o NI}{l}$

I is 0.2 A

$B = \frac{\mu_oN(0.2)}{l} = \frac{0.2\mu_o N}{l}$

$\frac{B}{0.2 } = \frac{\mu_o N}{l}$

$L = \frac{\mu_o N^2 A}{l} \\\\L = \frac{\mu_o N }{l} (NA)\\\\L = \frac{B}{0.2} (NA)\\\\L = \frac{BA}{0.2} (N)$

But Ф = BA

$L = \frac{\phi N}{0.2} \\\\\phi N = 0.2 L\\\\N = \frac{0.2 L}{\phi} \\\\N = \frac{0.2 *0.08}{8*10^{-6}}\\\\N = 2000 \ turns$

Therefore, the number of turns of the inductor is 2000 turns.

5 0

4 years ago

Two loudspeakers S1 and S2, 2.20 m apart, emit the same single-frequency tone in phase at the speakers. A listener L is located

seropon [69]

Answer:

the lowest possible frequency of the emitted tone is 404.79 Hz

Explanation:

Given the data in the question;

S₁ ← 5.50 m → L

↑

2.20 m

↓

S₂

We know that, the condition for destructive interference is;

Δr = ( 2m + $\frac{1}{2}$ ) × λ

where m = 0, 1, 2, 3 .......

Path difference between the two sound waves from the two speakers is;

Δr = √( 5.50² + 2.20² ) - 5.50

Δr = 5.92368 - 5.50

Δr = 0.42368 m

v = f × λ

f = ( 2m + $\frac{1}{2}$ )v / Δr

m = 0, 1, 2, 3, ....

Now, for the lowest possible frequency, let m be 0

f = ( 0 + $\frac{1}{2}$ )v / Δr

f = $\frac{1}{2}$ (v) / Δr

we know that speed of sound in air v = 343 m/s

so we substitute

f = $\frac{1}{2}$ (343) / 0.42368

f = 171.5 / 0.42368

f = 404.79 Hz

Therefore, the lowest possible frequency of the emitted tone is 404.79 Hz

5 0

3 years ago