1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
jeka94
3 years ago
12

One part of a freely swinging magnet always points

Physics
2 answers:
Sladkaya [172]3 years ago
8 0
One part of a freely swinging magnet always points to the Earth's magnetic pole in the Northern Hemisphere.
Readme [11.4K]3 years ago
3 0

Answer: The correct answer is (d).

Explanation:

Magnet has two poles: South pole and North pole. The same poles of the magnets repel each other. The opposite poles of the magnets attract each other.

In the absence of other magnet, a freely swinging magnet points in North-South direction. The earth has a magnetic field. The magnetic field of the bar magnet is same as the magnetic field of the earth's magnet.

The position of  the earth's magnetic poles are not fixed. The south pole of the earth's magnet lies in the geographic north as it attracts the north pole of the freely swinging magnet.

If one part of a freely suspended magnet always points to Earth's magnetic pole in the Northern Hemisphere.

You might be interested in
Consider the three dip1acement vectors A = (3i - 3j) m, B = (i-4j) m, and C = (-2i + 5j) m. Use the component method to determin
tia_tia [17]

Answer with Explanation:

We are given that

A=3i-3j m

B=i-4 j m

C=-2i+5j m

a.D=A+B+C

D=3i-3j+i-4j-2i+5j

D=2i-2j

Compare with the vector r=xi+yj

We get x=2 and y=-2

Magnitude=\mid D\mid=\sqrt{x^2+y^2}=\sqrt{(2)^2+(-2)^2}=2\sqrt 2 units

By using the formula \mid r\mid=\sqrt{x^2+y^2}

Direction:\theta=tan^{-1}\frac{y}{x}

By using the formula

Direction of D:\theta=tan^{-1}(\frac{-2}{2})=tan^{-1}(-1)=tan^{-1}(-tan45^{\circ})=-45^{\circ}

b.E=-A-B+C

E=-3i+3j-i+4j-2i+5j

E=-6i+12j

\mid E\mid=\sqrt{(-6)^2+(12)^2}=13.4units

Direction of E=\theta=tan^{-1}(\frac{12}{-6}=tan^{-1}(-2)=-63.4^{\circ}

4 0
3 years ago
Please help
ivanzaharov [21]

Answer:

1 +2=3 so thats it

Explanation:

Because i need points

4 0
3 years ago
©
Andru [333]

Answer:

Two positively charged particles

Explanation:

I said two positively charged particles because if I say c or d what ever it is for you guy it can be wrong so just pick the one that says Two positively charged particles

8 0
2 years ago
An electric bulb is marked 40volts ,230w another bulb is marked 40w,110v
Andrej [43]

Answer:

a. The ratio of their resistance is 2783:64

b. The ratio of their energy is 4:23

c. The charge on the first bulb is 5.75 C

The charge on the second bulb is 0.\overline {36} C

Explanation:

The voltage on one of the electric bulbs, V₁ = 40  volts

The power rating of the bulb, P₁ = 230 w

The voltage on the other electric bulbs, V₂ = 110 volts

The power rating of the bulb, P₂ = 40 w

a. The power is given by the formula, P = I·V = V²/R

Therefore, R = V²/P

For the first bulb, the resistance, R₁ = 40²/230 ≈ 6.96

The resistance of the second bulb, R₂ = 110²/40

The ratio of their resistance, R₂/R₁ = (110²/40)/(40²/230) = 2783/64

∴ The ratio of their resistance, R₂:R₁ = 2783:64

b. The energy of a bulb, E = t × P

Where;

t = The time in which the bulb is powered on

∴ The energy of the first bulb, E₁ = 230 w × t

The energy of the second bulb, E₂ = 40 w × t

The ratio of their energy, E₂/E₁ = (40 w × t)/(230 w × t) = 4/23

∴ The ratio of their energy, E₂:E₁ = 4:23

c. The charge on a bulb, 'Q', is given by the formula, Q = I × t

Where;

I = The current flowing through the bulb

From P = I·V, we get;

I = P/V

For the first bulb, the current, I = 230 w/40 V = 5.75 amperes

The charge on the first bulb per second (t = 1) is therefore;

Q₁ = 5.75 A × 1 s = 5.75 C

The charge on the first bulb, Q₁ = 5.75 C

Similarly, the charge on the second bulb, Q₂ = (40 W/110 V) × 1 s = 0.\overline {36} C

The charge on the second bulb, Q₂ = 0.\overline {36} C.

d. The question has left out parts

4 0
2 years ago
A mass of (200 g) of hot water at (75.0°C) is mixed with cold water of mass M at (5.0°C). The final temperature of the mixture i
SIZIF [17.4K]

The mass of the cold water, given the data from the question is 500 g

<h3>Data obtained from the question</h3>
  • Mass of warm water (Mᵥᵥ) = 200 g
  • Temperature warm water (Tᵥᵥ) = 75 °C
  • Temperature of cold water (T꜀) = 5 °C
  • Equilibrium temperature (Tₑ) = 25 °C
  • Specific heat capacity of the water = 4.184 J/gºC
  • Mass of cold water (M꜀) =?

<h3>How to determine the mass of the cold water </h3>

Heat loss = Heat gain

MᵥᵥC(Tᵥᵥ – Tₑ) = M꜀C(Tₑ – T꜀)

200 × 4.184 (75 – 25) = M꜀ × 4.184(25 – 5)

41840 = M꜀ × 83.68

Divide both side 83.68

M꜀ = 41840 / 83.68

M꜀ = 500 g

Learn more about heat transfer:

brainly.com/question/6363778

#SPJ1

4 0
2 years ago
Other questions:
  • 150-N box is being pulled horizontally in a wagon accelerating uniformly at 3.00 m/s2. The box does not move relative to the wag
    13·1 answer
  • A race-car drives around a circular track of radius RRR. The race-car speeds around its first lap at linear speed v_iv i ​ v, st
    15·1 answer
  • A fragment of a collapsing gas cloud that comes to equilibrium with a central temperature of 4 million k will become a:
    11·1 answer
  • How do you answer this. Need help ASAP. Offering 20 points !!!
    12·1 answer
  • In what type of change is matter not destroyed
    14·2 answers
  • The warmest layer of Earth's atmosphere is the ___.
    7·1 answer
  • Stacy travels 5 times as fast as Eric. Traveling in opposite directions, they are 336 miles apart after 4 hours. Find their rate
    6·1 answer
  • An object of mass m is moving down an inclined plane that makes an angle they a with the horizontal and has height h. Which of t
    12·1 answer
  • What is the period of a sound wave having a frequency of 340 Hz
    7·2 answers
  • The difference between a molecule and a compound is that a compound is made up of atoms from . A chemical change creates a new .
    6·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!