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Answer:
309 liters
Explanation:
A wonderful constant within the gas laws states that 1 mole of any gas occupies 22.4 liters at STP. ANY gas. Make that into a conversion factor you can use at your next social gathering if you want to annoy some friends:
(22.4L/1 mole) for any gas at STP.
Use that factor to find the answer:
(13.8 moles)(22.4L/1 mole) = 309 liters
Filtration. A filter is a porous barrier. Heterogeneous means it's a visible mixture, i.e large enough particles to see.
the final concentration of NaI solution in 60 grams/litre.
Explanation:
Given that:
Initial concentration of NaI solution M1 = 0.2 M
initial volume of NaI V1 = 2 L
Final volume V2 = 1 Litre
Final molarity=?
concentration in grams/litre = ?
molar mass of NaI = 150 gram/mole
For dilution following formula is used:
M1 V1 = M2V2
putting the values in the equation
0.2 X 2 = 1 X M2
M2 = 0.4
For concentration in grams/litre, formula used
molarity = ![\frac{mass}{atomic mass of one mole}](https://tex.z-dn.net/?f=%5Cfrac%7Bmass%7D%7Batomic%20mass%20of%20one%20mole%7D)
mass = 0.4 x 150
= 60 grams
So, 60 grams of NaI will be present in final solution of NaI after evaporation.
The concentration is 60 grams/ L (as volume got reduced to 1 litre from 2 litres)