The sulfuric acid can be constituted into different concentrations using distilled water as a diluent.
<h3>What is dilution of acid?</h3>
Dilution of acid is defined as the decrease in the concentration of an acid using water.
For sulfuric acid to be diluted, it is slowly added to distilled water using the following guidelines:
- Add 150 ml of water to the beaker and add the desired amount of acid. This will give a diluted concentration of the given acid.
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76.88 I think im sorry if wrong
Answer:
Explanation:
Iodine - 125
The atomic symbol of iodine is ¹²⁵₅₃ I
The symbol for iodine is I
The atomic number of iodine is 53,
and the atomic mass of iodine is 125 .
<u>The representation of the atomic symbol is as, the atomic mass is written in uppercase and the atomic number is written in lower case , followed by the symbol of the element .</u>
Iodine is a radio active element , used for many biological process .
It is the second largest -lived radioisotope of iodine .
The first is iodine-129 .
The balanced reaction is:
N2 + 3H2 = 2NH3
We are given the amount of the product to be produced.This will be the starting point of our calculations. We use the ideal gas equation to find for the number of moles.
<span>
n = PV / RT = 1.00(.520 L) / (0.08206 atm L/mol K ) 273 K
n= 0.0232 mol NH3
</span>0.0232 mol NH3 (1 mol N2 / 2 mol NH3) = 0.0116 mol N2
<span>Therefore, the correct answer is A.</span>
The balanced chemical reaction is:
<span>3N2H4(l)→4NH3(g)+N2(g)
</span>
The amounts given for the N2H4 reactant will be the starting point for our calculations.
2.6mol N2H4 ( 4 mol NH3 / 3 mol N2H4 ) = 3.47 mol NH3
4.05mol N2H4 ( 4 mol NH3 / 3 mol N2H4 ) = 5.4 mol NH3
63.8g N2H4 <span>( 4 mol NH3 / 3 mol N2H4 ) = 85.07 mol NH3</span>
