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gregori [183]
3 years ago
14

In the laboratory you are asked to make a 0.175 m barium iodide solution using 13.9 grams of barium iodide. How much water shoul

d you add?
Chemistry
1 answer:
BARSIC [14]3 years ago
4 0

<u>Answer:</u> The mass of water that should be added in 203.07 grams

<u>Explanation:</u>

To calculate the molality of solution, we use the equation:

\text{Molality}=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}

Where,

m = molality of barium iodide solution = 0.175 m

m_{solute} = Given mass of solute (barium iodide) = 13.9 g

M_{solute} = Molar mass of solute (barium iodide) = 391.14 g/mol

W_{solvent} = Mass of solvent (water) = ? g

Putting values in above equation, we get:

0.175=\frac{13.9\times 1000}{391.14\times W_{solvent}}\\\\W_{solvent}=\frac{13.9\times 1000}{391.14\times 0.175}=203.07g

Hence, the mass of water that should be added in 203.07 grams

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What are the number if protons, neutrons, and electrons
marishachu [46]

protons and electrons are both always the atomic number which is 9 in this case.

For neutrons you subtract the atomic number (9) from the weight of the atom (18.998) some teachers will want you to round to the nearest whole (19). We do this because the number of protons is the atomic number so if you subtract the protons from the whole weight of the atom you would have the electrons and neutrons left. Since electrons weigh so little we don't have to subtract them. Weighing neutrons and electrons would be like weighing an elephant (neutrons) and then putting one marshmallow on the scale (electron).  

5 0
3 years ago
Calculate the density of air at 100 Deg C and 1 bar abs. Use the Ideal Gas Law for your calculation and give answer in kg/m3. Us
madam [21]

Answer:

d=0.92\frac{kg}{m^{3}}

Explanation:

Using the Ideal Gas Law we have PV=nRT and the number of moles n could be expressed as n=\frac{m}{M}, where m is the mass and M is the molar mass.

Now, replacing the number of moles in the equation for the ideal gass law:

PV=\frac{m}{M}RT

If we pass the V to divide:

P=\frac{m}{V}\frac{RT}{M}

As the density is expressed as d=\frac{m}{V}, we have:

P=d\frac{RT}{M}

Solving for the density:

d=\frac{PM}{RT}

Then we need to convert the units to the S.I.:

T=100^{o}C+273.15

T=373.15K

P=1bar*\frac{0.98atm}{1bar}

P=0.98atm

M=28.9\frac{kg}{kmol}*\frac{1kmol}{1000mol}

M=0.0289\frac{kg}{mol}

Finally we replace the values:

d=\frac{(0.98atm)(0.0289\frac{kg}{mol})}{(0.082\frac{atm.L}{mol.K})(373.15K)}

d=9.2*10^{-4}\frac{kg}{L}

d=9.2*10^{-4}\frac{kg}{L}*\frac{1L}{0.001m^{3}}

d=0.92\frac{kg}{m^{3}}

5 0
3 years ago
i need help i have a homework assignment to finish and this is the last question help please and thank u
Jet001 [13]
A
i just searched it up and wanted to help
5 0
3 years ago
HELP PLEASE!
Yuki888 [10]

Answer:

1. Carbon dioxide, increase of green house gas

2. Stop deforestation, cut down amount of cars on the road (encourage public to take public transport), reduce the amount of time u on the air-conditioning

4 0
3 years ago
A chemist dilutes 185 of the 3.0 M solution with water until a new volume of 750 is obtained. Calculate the new concentration
svlad2 [7]

Answer:

0.74M

Explanation:

Step 1 :

Data obtained from the question.

Initial concentration (C1) = 3M

Initial volume (V2) = 185mL

Final volume (V2) = 750mL

Final concentration (C2) =..?

Step 2:

Determination of the new concentration of the solution.

The new concentration of the solution can be obtained by using the dilution formula as shown below:

C1V1 = C2V2

3 x 185 = C2 x 750

Divide both side by 750

C2 = 3 x 185 / 750

C2 = 0.74M

Therefore, the new concentration of the solution is 0.74M

7 0
3 years ago
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