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max2010maxim [7]
3 years ago
10

Of the following solutions, which has the greatest buffering capacity?

Chemistry
1 answer:
Goshia [24]3 years ago
4 0

Answer:

d. 0.121 M HC2H3O2 and 0.116 M NaC2H3O2

Explanation:

Hello,

In this case, since the pH variation is analyzed via the Henderson-Hasselbach equation:

pH=pKa+log(\frac{[Base]}{[Acid]} )

We can infer that the nearer to 1 the ratio of of the concentration of the base to the concentration of the acid the better the buffering capacity. In such a way, since the sodium acetate is acting as the base and the acetic acid as the acid, we have:

a. \frac{[Base]}{[Acid]}=\frac{0.497M}{0.365M}=1.36

b. \frac{[Base]}{[Acid]}=\frac{0.217M}{0.521M}=0.417

c. \frac{[Base]}{[Acid]}=\frac{0.713M}{0.821M}=0.868

d. \frac{[Base]}{[Acid]}=\frac{0.116M}{0.121M}=0.959

Therefore, the d. solution has the best buffering capacity.

Regards.

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What conditions will cause a redox reaction to be nonspontaneous?
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7 0
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Match each statement with one of these terms.
skelet666 [1.2K]

Answer:

1 - e, 2 - k, 3 - a, 4 - i, 5 - b,

Explanation:

The ratio of the amount of analyte in the stationary phase to the amount in the mobile phase. --- Retention factor.

Time it takes after sample injection into the column for the analyte peak to appear as it exits the column. -- Retention time

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8 0
3 years ago
Calculate the percentage yield for the reaction represented by the equation CH4 + 2O2 ? 2H2O + CO2 when 1000 g of CH2 react with
makvit [3.9K]

Answer:

83.64%.

Explanation:

∵ The percent yield = (actual yield/theoretical yield)*100.

actual yield of CO₂ = 2300 g.

  • We need to find the theoretical yield of CO₂:

For the reaction:

<em>CH₄ + 2O₂ → 2H₂O + CO₂,</em>

1.0 mol of CH₄ react with 2 mol of O₂ to produce 2 mol of H₂O and 1.0 mol of CO₂.

  • Firstly, we need to calculate the no. of moles of 1000 g of CH₄ using the relation:

<em>no. of moles of CH₄ = mass/molar mass</em> = (1000 g)/(16.0 g/mol) = <em>62.5 mol.</em>

<u><em>Using cross-multiplication:</em></u>

1.0 mol of CH₄ produces → 1.0 mol of CO₂, from stichiometry.

∴ 62.5 mol of CH₄ produces → 62.5 mol of CO₂.

  • We can calculate the theoretical yield of carbon dioxide gas using the relation:

∴ The theoretical yield of CO₂ gas = n*molar mass = (62.5 mol)(44.0 g/mol) = 2750 g.

<em>∵ The percent yield = (actual yield/theoretical yield)*100.</em>

actual yield = 2300 g, theoretical yield = 2750 g.

<em>∴ the percent yield</em> = (2300 g/2750 g)*100 = <em>83.64%.</em>

5 0
4 years ago
If the density of a certain spherical atomic nucleus is 1.0 _ 1014 g cm_3 and its mass is 2.0 _ 10_23 g, what is its radius in c
melamori03 [73]
1) Calculate the volume from d = m/V => V = m/d = 2.0*10^-23 g /  1.0*10^14 g/cm^3 = 2.0*10^-9 cm^3

2) Now use the formula of volume for a sphere: V = (4/3)π(r^3) =>

r =∛[3V/(4π)] = ∛[(3*2.0*10^-9 cm^3) / (4π)] = 0.48*10^-3 cm = 4.8*10^-4 cm = 0.00048cm
5 0
3 years ago
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