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Citrus2011 [14]
4 years ago
15

Which statements accurately describe mass? Check all that apply.

Chemistry
1 answer:
Alexxandr [17]4 years ago
4 0

Answer:

the second,third and last statement

Explanation:

please like and Mark as brainliest

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When 3243. grams of iron (III) chloride are reacted with 511.8 grams of hydrosulfuric acid, which is the limiting reactant?
AleksAgata [21]

Answer:

Hydrosulfuric acid will act as limiting reactant.

Explanation:

Given data:

Mass of iron(III) chloride = 3243.0 g

Mass of hydrosulfuric acid = 511.8 g

Limiting reactant = ?

Solution:

Chemical equation:

2FeCl₃ + 3H₂S       →       Fe₂S₃ + 6HCl

Number of moles of iron(III) chloride:

Number of moles = mass/molar mass

Number of moles = 3243.0 g/ 162.2 g/mol

Number of moles = 20 mol

Number of moles of hydrosulfuric acid:

Number of moles = mass/molar mass

Number of moles = 511.8 g/ 34.1 g/mol

Number of moles = 15 mol

Now we will compare the moles of both reactant with products

                      FeCl₃          :          Fe₂S₃

                       2                :            1

                      20               :          1/2 ×20 = 10

                      FeCl₃          :            HCl

                       2                :              6

                      20               :          6/2 ×20 = 60

                      H₂S             :          Fe₂S₃

                       3                :            1

                      15               :          1/3 ×15 = 5

                      H₂S            :            HCl

                       3                :              6

                      15                :          6/3 ×15 = 30

Hydrosulfuric acid producing less number of moles of product thus, it will act as limiting reactant.

 

5 0
3 years ago
How many moles of I2 will form 3.58 g of NI3?
Mila [183]

1.       The balanced chemical reaction is:

 

N2 +3 I2 = 2NI3

 

We are given the amount of product formed. This will be the starting point of our calculations.

 

3.58 g NI3 ( 1 mol NI3 / 394.71 g NI3 ) ( 3 mol I2 / 2 mol NI3 ) = 0.014 mol I2.

 

Thus, 0.014 mol of I2 is needed to form the given amount of NI3.

6 0
3 years ago
Suppose a helium-3 nuclide transforms into a helium-4 nuclide by absorbing a proton and emitting a positron. Complete the nuclea
saw5 [17]

<u>Answer:</u> The nuclear equation for the conversion of He-3 nuclide to He-4 nuclide is given above.

<u>Explanation:</u>

Nuclear reaction are defined as the reactions in which nucleus of an atom is involved.

Positron emission is defined as the emission process in which positron particle is emitted. In this process, a proton gets converted to neutron and an electron neutrino particle.

_Z^A\textrm{X}\rightarrow _{Z-1}^A\textrm{Y}+_{+1}^0e

The chemical equation for the reaction of He-3 with a proton follows:

_2^3\textrm{He}+_1^1\textrm{H}\rightarrow _2^4\textrm{He}+_{+1}^0e

Hence, the nuclear equation for the conversion of He-3 nuclide to He-4 nuclide is given above.

6 0
3 years ago
If ethanol has a density of 0.785g/mL, calculate the volume of 83.7 g of ethanol.
ratelena [41]

Answer:

<h2>106.62 mL</h2>

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

volume =  \frac{mass}{density} \\

From the question

mass = 83.7 g

density = 0.785 g/mL

We have

volume =  \frac{83.7}{0.785}  \\  = 106.62420

We have the final answer as

<h3>106.62 mL</h3>

Hope this helps you

8 0
3 years ago
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andrew11 [14]
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6 0
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