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Rufina [12.5K]
3 years ago
10

Calculate the percentage yield for the reaction represented by the equation CH4 + 2O2 ? 2H2O + CO2 when 1000 g of CH2 react with

excess O2 to produce 2300 g of CO2.
Chemistry
1 answer:
makvit [3.9K]3 years ago
5 0

Answer:

83.64%.

Explanation:

∵ The percent yield = (actual yield/theoretical yield)*100.

actual yield of CO₂ = 2300 g.

  • We need to find the theoretical yield of CO₂:

For the reaction:

<em>CH₄ + 2O₂ → 2H₂O + CO₂,</em>

1.0 mol of CH₄ react with 2 mol of O₂ to produce 2 mol of H₂O and 1.0 mol of CO₂.

  • Firstly, we need to calculate the no. of moles of 1000 g of CH₄ using the relation:

<em>no. of moles of CH₄ = mass/molar mass</em> = (1000 g)/(16.0 g/mol) = <em>62.5 mol.</em>

<u><em>Using cross-multiplication:</em></u>

1.0 mol of CH₄ produces → 1.0 mol of CO₂, from stichiometry.

∴ 62.5 mol of CH₄ produces → 62.5 mol of CO₂.

  • We can calculate the theoretical yield of carbon dioxide gas using the relation:

∴ The theoretical yield of CO₂ gas = n*molar mass = (62.5 mol)(44.0 g/mol) = 2750 g.

<em>∵ The percent yield = (actual yield/theoretical yield)*100.</em>

actual yield = 2300 g, theoretical yield = 2750 g.

<em>∴ the percent yield</em> = (2300 g/2750 g)*100 = <em>83.64%.</em>

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Answer:

pH = 6.999

The solution is acidic.

Explanation:

HBr is a strong acid, a very strong one.

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We can think pH, as - log 7.75×10⁻¹² but this is 11.1

acid pH can't never be higher than 7.

We apply the charge balance:

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<u>Answer:</u> 4.999 moles of excess reactant will be left over.

<u>Explanation:</u>

Limiting reagent is defined as the reagent which is completely consumed in the reaction and limits the formation of the product.

Excess reagent is defined as the reagent which is left behind after the completion of the reaction.

The number of moles is defined as the ratio of the mass of a substance to its molar mass.

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}       .....(1)

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