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Rufina [12.5K]
4 years ago
10

Calculate the percentage yield for the reaction represented by the equation CH4 + 2O2 ? 2H2O + CO2 when 1000 g of CH2 react with

excess O2 to produce 2300 g of CO2.
Chemistry
1 answer:
makvit [3.9K]4 years ago
5 0

Answer:

83.64%.

Explanation:

∵ The percent yield = (actual yield/theoretical yield)*100.

actual yield of CO₂ = 2300 g.

  • We need to find the theoretical yield of CO₂:

For the reaction:

<em>CH₄ + 2O₂ → 2H₂O + CO₂,</em>

1.0 mol of CH₄ react with 2 mol of O₂ to produce 2 mol of H₂O and 1.0 mol of CO₂.

  • Firstly, we need to calculate the no. of moles of 1000 g of CH₄ using the relation:

<em>no. of moles of CH₄ = mass/molar mass</em> = (1000 g)/(16.0 g/mol) = <em>62.5 mol.</em>

<u><em>Using cross-multiplication:</em></u>

1.0 mol of CH₄ produces → 1.0 mol of CO₂, from stichiometry.

∴ 62.5 mol of CH₄ produces → 62.5 mol of CO₂.

  • We can calculate the theoretical yield of carbon dioxide gas using the relation:

∴ The theoretical yield of CO₂ gas = n*molar mass = (62.5 mol)(44.0 g/mol) = 2750 g.

<em>∵ The percent yield = (actual yield/theoretical yield)*100.</em>

actual yield = 2300 g, theoretical yield = 2750 g.

<em>∴ the percent yield</em> = (2300 g/2750 g)*100 = <em>83.64%.</em>

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tia_tia [17]

Answer:

It can use a small amount of sunlight for photosynthesis

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Seaweeds are a group of marine plants/algae that grow attached to rocks underwater. However, despite their depth underwater, they still perform photosynthesis, which is a process that requires energy from sunlight.

Seaweeds are able to perform photosynthesis underwater because they are efficient users of sunlight energy. Hence, they require only a small amount of sunlight that penetrates the ocean to perform photosynthesis.

8 0
3 years ago
26.5 g of a solution with a density of 7.48 g/mL
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Answer:  Assuming the question: 3.54 ml (3 sig figs)

Explanation:

I don't see a question, but will assume it is "What volume is needed to obtain 26.5 grams?

If so:

(26.5 g)/(7.48 ml) = 3.54 ml (3 sig figs)

6 0
3 years ago
What is the ratio of lactic acid (Ka = 1.37x10-4) to lactate in a solution with pH =4.49?
Natasha2012 [34]
When Ka =1.37 x 10^-4 

∴Pka = - ㏒Ka

          = -㏒ 1.37 x 10^-4 
          
           = 3.86

According to H- H equation: 

when PH = PKA + ㏒[conjugate base / weak acid]

when the lactate is the conjugate base and lactic acid is the weak acid 

∴ PH = Pka +㏒[lactate] / [lactic acid]

so, by substitution:


4.49 = 3.86 + ㏒[lactate]/[lactic acid]

∴[lactate]/[lactic acid] = 4.3

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3 years ago
Metal X has a specific heat capacity of 0.982 Jg∙°C . If 525.0 g of Metal X increases in temperature from 32.00° C to 43.00° C,
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Answer:

Q = 5671.05 J

Explanation:

Given data:

Mass of metal = 525 g

Initial temperature = 32.0 °C

Fina temperature = 43.0 °C

Heat absorbed by metal = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

specific heat capacity of metal X = 0.982 J/g.°C

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

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ΔT = 11.00°C

Q = 525 g × 0.982 J/g.°C  × 11.00°C

Q = 5671.05 J

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