3 years ago

Tomlin is removing the wallpaper the wallpaper covers 5 meter by 4 meter rectangular wall how much wallpaper will tomlin remove

Mathematics

1 answer:

Ksenya-84 [330]3 years ago

4 0

Answer:

20 meters. I need to have 20

You might be interested in

Adrianna, Deon, and Yoko jogged at Eisenhower Park today. Adrianna jogs at the park every 3

Dominik [7]

Answer:the answer is 30

Step-by-step explanation hope this helped ☺️

3 0

3 years ago

This year, jake is 5 years older than his sister. Three years ago, jake was twice his sisters age. How old is jakes sister now?

ruslelena [56]

you don't have enough info, we need to know how old he was when he was twice her age, or how old she was

6 0

3 years ago

Rewrite 13 over 7 as a mixed number

antoniya [11.8K]

To simplify mixed numbers, Divide 13 and 7. We get 1 R 6. Since the remainder is out of 7, the mixed number would be 1 6/7

Hope this helps!

3 0

3 years ago

Read 2 more answers

Plz help with equation of the circle will award fastest CORRECT answer with brainliest

aliina [53]

Answer:

$(x-1)^2+(y-2)^2=6.25$

Step-by-step explanation:

The equation for a circle is given by:

$(x-h)^2+(y-k)^2=r^2$

Where (h,k) is the center and r is the radius.

The center is the red dot, which is (1,2). Thus, h=1 and k=2.

To find the radius, you need to use the distance formula. We are given two coordinates: the center (red dot) at (1,2) and a blue dot on the circle at (2.5,4). Find the radius by using the distance formula:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Let (1,2) be x₁ and y₁ and let (2.5,4) be x₂ and y₂. Therefore:

$d=\sqrt{(2.5-1)^2+(4-2)^2}\\d=\sqrt{(1.5)^2+2^2}\\d=\sqrt{2.25+4}\\d=\sqrt{6.25}=2.5$

Thus, r is 2.5.

Plugging these numbers into the equation, we have:

$(x-h)^2+(y-k)^2=r^2\\(x-1)^2+(y-2)^2=2.5^2\\(x-1)^2+(y-2)^2=6.25$

3 0

3 years ago

Numa P.A de razão 6, o primeiro termo é 2. Qual a posição do termo igual a 34? ( Me ajudem pfvr é pra hoje )

EastWind [94]

Será que hasta responden en este idioma x que yo no se

8 0

3 years ago