When the nuclear half-life of the radioactive isotope is showing the time needed for the isotope to be half of its initial value of mass.
so with each half-life, the isotope will be halved of its initial value as example:
after the first half-life, the isotope will lose 50 % of its initial value
and after the second half-life, the isotope will lose 25% of its initial value
and after the third half-life, the isotope will lose 12.5 % of its initial value
and so on,
So here to get how many numbers of half-lives we will use this formula:
numbers of half-lives = total time passed / the half-life of the isotope
= 30 days / 14 days
=2 days
∴remainig mass = initial mass / 2^numbers of half-lives
= 10 g / 2^2
= 2.5 g
Answer:
Hey kimalonzo59!
· Calculate specific heat as c = Q / (mΔT). In our example, it will be equal to c = -63,000 J / (5 kg * -3 K) = 4,200 J/ (kg·K). This is the typical heat capacity of water.
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