Answer:
- 273.77 rad/s^2
Explanation:
fo = 3800 rev/min = 3800 / 60 rps = 63.33 rps
f = 0
ωo = 2 π fo = 2 x 3.14 x 63.33 = 397.71 rad/s
ω = 2 π f = 0
θ = 46 revolutions = 46 x 2π radian = 288.88 radian
Let α be the angular acceleration of the centrifuge
Use third equation of motion for rotational motion
α = - 273.77 rad/s^2
Answer:
Speed: 4.8 m/s
Velocity: 4.8 m/s north
Explanation:
Definitions:
- Speed is a scalar quantity, which is equal to the ratio between distance covered (d) and time taken (t):
- Velocity is a vector quantity, whose magnitude is equal to the ratio between the displacement of the object and the time taken:
And it also has a direction (the same as the displacement).
In this problem:
- The object travels a distance of
d = 105 m
In a time interval of
t = 22 s
So its speed is
- The displacement of the object is the same as the distance in this case, so still 105 m, covered in a time interval of 22 s; this means that the magnitude of the velocity is the same as the speed:
However, velocity is a vector quantity, so it also has a direction: and since the object has moved north, the direction of the velocity is north as well.