All categories

3 years ago

A Object has a constant mass . If the force increases, the acceleration will ...

Physics

2 answers:

Nadusha1986 [10]3 years ago

8 0

Answer:

increase

Explanation:

mina [271]3 years ago

4 0

Answer:

Increase

Explanation:

A force that acts on an object causes the object to accelerate.

F=ma

When mass is kept constant, force is directly proportional to the acceleration. Meaning that if the force increases, the acceleration increases, and if force decreases the acceleration decreases.

When force is kept constant, acceleration is inversely proportional to mass.

Meaning that when the mass of the objet increases, the acceleration of the object will decrease, and if the mass of the object decreases, the acceleration will increase.

Hope this helped!

You might be interested in

Which explanation of the solar system best fits the observations of the planets and how they orbit the sun? (Points : 3)

AURORKA [14]

From those choices, the best is the third one. it relates to why the sun and almost everything else in the solar system spins in the same direction, and also why the abundance of various elements in the planets is so different from what it is in the sun.

7 0

3 years ago

A test of the prototype of a new automobile shows that the minimum distance for a controlled stop from 95 km/h to zero is 55 m.

iris [78.8K]

Answer:

-0.64525g

Explanation:

t = Time taken for the car to stop

u = Initial velocity = 95 km/h

v = Final velocity = 0 km/h

s = Displacement

a = Acceleration

Equation of motion

$v^2-u^2=2as\\\Rightarrow a=\frac{v^2-u^2}{2s}\\\Rightarrow a=\frac{0^2-95^2}{2\times 0.055}\\\Rightarrow a=-82045.45\ km/h^2$

Converting to m/s²

$a=82045.45=\frac{82045.45\times 1000}{3600\times 3600}=-6.33\ m/s^2$

g = Acceleration due to gravity = 9.81 m/s²

Dividing both the accelerations, we get

$\frac{a}{g}=\frac{-6.33}{9.81}=-0.64525\\\Rightarrow a=-0.64525g$

Hence, acceleration of the car is -0.64525g

8 0

4 years ago

Late one night on a highway, a car speeds by you and fadesinto the distance. Under these conditions the pupils of your eyes(aver

Andrews [41]

Answer:

10432.19076 m

Explanation:

$\lambda$ = Wavelength = 660 nm

d = Diameter of pupils = 6 mm

s = Distance between lights = 1.4 m

L = Distance from observer

From Rayleigh's criteria we have

$1.22\lambda=dsin\theta$

As $\theta$ is small $sin\theta=\dfrac{s}{L}$

So, the equation becomes

$1.22\lambda=d\dfrac{s}{L}\\\Rightarrow L=\dfrac{ds}{1.22\lambda}\\\Rightarrow L=\dfrac{6\times 10^{-3}\times 1.4}{1.22\times 660\times 10^{-9}}\\\Rightarrow L=10432.19076\ m$