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3 years ago

What is the difference between electromotive force and potential difference?

1 answer:

3 0

The electric charge that has been separated creates an electric potential difference that can be measured with a voltmeter between the terminals of the device. The magnitude of the emf for the battery (or other source) is the value of this 'open circuit' voltage.

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If you run the simulation a few times, you should see that for this particular pair of block and disc the block's position has t

user100 [1]

Explanation:

C) is incorrect. The mass is equivalent to the moment of inertia in an angular formula.

The others appear all correct.

T * theta = F * r * theta = F * (r theta) = fx = work

This is the only one that needed explanation. The others should be obvious.

7 0

3 years ago

A hockey goalie is standing on ice. Another player fires a puck (m = 0.170 kg) at the goalie with a velocity of +41.0 m/s. (a) I

viktelen [127]

Answer:

2991.42 N

Explanation:

For this problem, we'll use the equations: momentum= mass x velocity and impulse = change in momentum, and impulse=force x time.

initial momentum; p1 = 0.17 x 41 = 6.97 kg.m/s

final momentum; p2 = 0, because final velocity is 0 m/s

Thus,

impulse = p1 - p2= 6.97 - 0 = 6.97 kg.m/s

Finally, impulse= Force x time,

Thus, Force = Impulse/time

Force= 6.97/ (2.33 x 10^(-3)) = 2991.42 N

4 0

4 years ago

Why don't you notice your gravitational force on other objects?

mixas84 [53]

The answer is B tell me if I am wrong.

4 0

3 years ago

Read 2 more answers

Two electric charges qa = 1. 0 μc and qb = - 2. 0 μc are located 0. 50 m apart. how much work is needed to move the charges apar

melisa1 [442]

The total work done of 0.018 joules is needed to move the charges apart and double the distance between them.

We have two electric charges q(A) = 1μc and q(B) = -2μc kept at a distance 0.5 meter apart.

We have to calculate much work is needed to move the charges apart and double the distance between them.

<h3>What s the formula to calculate the Potential Energy of a system of two charges (say 'q' and 'Q') separated by a distance 'r' ?</h3>

The potential energy of the system of two charges separated by a distance is given by -

$U = \frac{1}{4\pi\epsilon_{o} } \frac{qQ}{r}$

In order to solve this question, it is important to remember the work - energy theorem which states -

"The change in the energy of the body is equal to work done on it"

Hence, using this work -energy theorem in the question given to us we get -

$U_{f} -U_{i} =W_{net}$

In our case -

$U_{f} = \frac{1}{4\pi\epsilon_{o} } \frac{qQ}{2r}\\\\U_{i} = \frac{1}{4\pi\epsilon_{o} } \frac{qQ}{r}\\\\W=\frac{1}{4\pi\epsilon_{o} } \frac{qQ}{2r} - \frac{1}{4\pi\epsilon_{o} } \frac{qQ}{r}\\\\W = \frac{qQ}{4\pi\epsilon_{o}r} (\frac{1}{2} -1)\\\\W = 9\times 10^{9}\times \frac{1 \times 10^{-6} \times 2\times10^{-6} }{0.5} \times \frac{-1}{2}$

W = 0.018 joules

Hence, the total work done should be 0.018 joules.

To solve more question on potential energy, visit the link below -

brainly.com/question/15014856

#SPJ4

4 0

2 years ago

Matthew drives 10 meters to go to the park at her the park he goes to the movie theatre which is 15 meters away from the park. H

Step2247 [10]

Answer: 0 m

Explanation:

Let's begin by stating clear that movement is the change of position of a body at a certain time. So, during this movement, the body will have a trajectory and a displacement, being both different:

The trajectory is the path followed by the body (is a scalar quantity).

The displacement is the distance in a straight line between the initial and final position (is a vector quantity).

According to this, in the description Matthew's home is placed at 0 on a number line, then he moves 10 m to the park (this is the distance between the park and Mattew's home), then 15 m to the movie theatre until he finally comes back to his home (position 0). So, in this case we are talking about the path followed by Matthew, hence his trajectory.

However, if we talk about Matthew's displacement, we have to draw a straight line between Matthew's initial position (point 0) to his final position (also point 0).

Now, being this an unidimensional problem, the displacement vector for Matthew is 0 meters.

4 0

3 years ago