**Answer:**

**The mass of water required is, m = 1.492 Kg**

**The final temperature of water, = 100 °C**

**Explanation:**

Given that

Energy absorbed by water, q = 4.5 x 10⁵ J

The initial temperature of water = 25 °C

The mass of water required to absorb the energy, m = ?

The final temperature of water, = ?

The formula for energy absorbed by the water,

**q = m C ΔT Joules**

where,

C - specific heat capacity (4200 J/Kg °C)

ΔT = - (change in temperature)

The maximum possible temperature of the water at Standard Temperature and Pressure is 100 °C

As the final temperature is not given, let us consider the maximum possible temperature of the water.

Therefore,

ΔT = -

= 100 -25

= 75 °C

To find the mass of water, from the above relation

m = q/CΔT Kg

Substituting the values in the above equation

m = 4.5 x 10⁵/4200 x 75

m = 1.492 Kg

**Hence, the mass of water required is m = 1.492 Kg**