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3 years ago

5CaO4

Physics

1 answer:

RUDIKE [14]3 years ago

6 0

Answer:

a) 2

b) 9

c) 5

d) 14

e) 4

f) 5

Explanation:

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Suppose that on earth you can throw a ball vertically upward a distance of 1.20 m. Given that the acceleration of gravity on the

tatuchka [14]

Answer:

7.04 m

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity = 0

s = Displacement on Earth = 1.2 m

a = Acceleration due to gravity on Moon = 1.67 m/s²

a = Acceleration due to gravity Earth= 9.81 m/s²

Accelration going up is considered as negetive

Initial Velocity of the ball

$v^2-u^2=2as\\\Rightarrow -u^2=2as-v^2\\\Rightarrow -u^2=2\times -9.81\times 1.2-0^2\\\Rightarrow u=\sqrt{2\times 9.81\times 1.2}\\\Rightarrow u=4.85\ m/s$

Assuming that the ball is thrown with the same velocity on the Moon, displacement of the ball is

$v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{0^2-4.85^2}{2\times -1.67}\\\Rightarrow s=7.04\ m$

The displacement of the ball on the moon is 7.04 m

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3 years ago

How can you determine the number of valence electrons in atom without drawing a Bohr model?

grigory [225]

Using your periodic table if you look at it 3-11 are tansition metals so the horizontal Group Number will help if the group number has to digits just remove the one so if it were to be 13, the valence would be 3, if it were 14 the valence would be ,4 if it were 15, the valence would be 5, if it were 16 the valence would be 6, if it were 17 the valence would be 7 if it were group 18 the valence would be 8 so if anymore help needed to explain hit me up

5 0

3 years ago

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A 20.00 kg lead sphere is hanging from a hook by a thin, massless wire 2.80 m long and is free to swing in a complete circle. Tr

Tema [17]

The minimum initial speed of the dart so that the combination makes a complete circular loop after the collision is 58.5 m/s.

<h3>Minimum speed for the object not fall out of the circle</h3>

The minimum speed if given by tension in the wire;

T + mg = ma

T + mg = m(v²)/R

tension must be zero for the object not fall

0 + mg = mv²/R

v = √(Rg)

<h3>Final speed of the two mass after collision</h3>

Use the principle of conservation of energy

K.Ef = K.Ei + P.E

¹/₂mvf² = ¹/₂mv² + mg(2R)

¹/₂vf² = ¹/₂v² + g(2R)

¹/₂vf² = ¹/₂(Rg) + g(2R)

vf² = Rg + 4Rg

vf² = 5Rg

vf = √(5Rg)

vf = √(5 x 2.8 x 9.8)

vf = 11.7 m/s

<h3>Initial speed of the dart</h3>

Apply principle of conservation of linear momentum for inelastic collision;

5v = vf(20 + 5)

5v = 11.7(25)

5v = 292.5

v = 58.5 m/s

Learn more about linear momentum here: brainly.com/question/7538238

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2 years ago

A 4kg box is pressed into a spring. The spring constant k=220N/m. The box is released at the bottom of a frictionless ramp and r

AVprozaik [17]

Answer:

Explanation:

The stored elastic energy in the spring helps the box to rise to a height of .75 m

So stored elastic energy = potential energy attained

1/2 k d² = mgh , k is spring constant , d is compression in spring , m is mass of box , h is height attained .

Putting the values

.5 x 220 x d² = 4 x 9.8 x .75

d² = .2673

d = .517 m

51.7 cm .

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3 years ago

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Choose the correct answer to complete the sentence. You find some smooth, rounded rocks that are scattered around the ground. Yo

mote1985 [20]

These rocks can be any of the following listed but they cannot be solid aa lava. This is because solid aa lava would not be smooth, rounded rocks and would not be scattered on the ground.

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3 years ago