PE = mgh
where
m = mass
g = acceleration due to gravity
h = height
Mechanical advantage of a machine is the ratio of the output force over the input force or M=Fo/Fi. Since M=1, Fi=Fo, or the input force is equal to the output force. This means that to raise the refrigerator that weighs 900 N, we need the same input force of 900 N, or Fo=Fi=900 N.
<em>Resultant angle; θ = 25.59° </em>
This question is dealing with bearings and distance.
We are told that from point A, the camel walks 20 km at 15° in the south of east direction.
Thus, d_s,e = 20 km
Resolving along the horizontal east direction gives; d_e = 20 cos 15
d_e = 19.32 km
Also, resolving along the vertical south direction gives; d_s = 20 sin 15
d_s = 5.18 km
Net vertical distance; d_vert = 8km - 5.18km = 2.72 km
Net horizontal distance; d_hor = 25km - 19.32 km = 5.68 km
Now, the resultant angle is given by;
tan θ = d_vert/d_hor
tan θ = 2.72/5.68
tan θ = 0.4789
θ = tan^(-1) 0.4789
θ = 25.59°
Read more at; brainly.com/question/22518031
Answer:
The magnitude of the large object's momentum change is 3 kilogram-meters per second.
Explanation:
Under the assumption that no external forces are exerted on both the small object and the big object, whose situation is described by the Principle of Momentum Conservation:
(1)
Where:
,
- Initial and final momemtums of the small object, measured in kilogram-meters per second.
,
- Initial and final momentums of the big object, measured in kilogram-meters per second.
If we know that
,
and
, then the final momentum of the big object is:
![7\,\frac{kg\cdot m}{s} + 0\,\frac{kg\cdot m}{s} = 4\,\frac{kg\cdot m}{s}+p_{B,2}](https://tex.z-dn.net/?f=7%5C%2C%5Cfrac%7Bkg%5Ccdot%20m%7D%7Bs%7D%20%2B%200%5C%2C%5Cfrac%7Bkg%5Ccdot%20m%7D%7Bs%7D%20%3D%204%5C%2C%5Cfrac%7Bkg%5Ccdot%20m%7D%7Bs%7D%2Bp_%7BB%2C2%7D)
![p_{B,2} = 3\,\frac{kg\cdot m}{s}](https://tex.z-dn.net/?f=p_%7BB%2C2%7D%20%3D%203%5C%2C%5Cfrac%7Bkg%5Ccdot%20m%7D%7Bs%7D)
The magnitude of the large object's momentum change is:
![p_{B,2}-p_{B,1} = 3\,\frac{kg\cdot m}{s}-0\,\frac{kg\cdot m}{s}](https://tex.z-dn.net/?f=p_%7BB%2C2%7D-p_%7BB%2C1%7D%20%3D%203%5C%2C%5Cfrac%7Bkg%5Ccdot%20m%7D%7Bs%7D-0%5C%2C%5Cfrac%7Bkg%5Ccdot%20m%7D%7Bs%7D)
![p_{B,2}-p_{B,1} = 3\,\frac{kg\cdot m}{s}](https://tex.z-dn.net/?f=p_%7BB%2C2%7D-p_%7BB%2C1%7D%20%3D%203%5C%2C%5Cfrac%7Bkg%5Ccdot%20m%7D%7Bs%7D)
The magnitude of the large object's momentum change is 3 kilogram-meters per second.
Answer:
The answer is B.
Explanation:
They are in control of the experiment, they can change it the variables to better help the experiment.