Assuming the atmospheric pressure is 1 atm at sea level, determine the atmospheric pressure at Badwater (in Death Valley, Califo
1 answer:
Answer:
Atmospheric pressure at Badwater is 1.01022 atm
Explanation:
Data given:
1 atmospheric pressure (Pi) = 1.01 * 10 Pa
Elevation (h) = 86m
gravity (g) = 9.8 m/s2
Density of air P = 1.225 kg/m3
Therefore pressure at bad water Pb = Pi + Pgh
Pb = (1.01 * 10) + (1.225 * 9.8 * 86)
Pb = (1.01 * 10) + 1032.43 = 102032 Pa
hence:
Pb = 102032 /1.01 * 10 = 1.01022 atm
You might be interested in
Answer:
Induced emf in the loop is 0.0603 volts.
Explanation:
It is given that,
Radius of the circular loop, r = 1.6 cm = 0.016 m
Magnetic field, B = 0.8 T
When released, the radius of the loop starts to shrink at an instantaneous rate of 75.0 cm/s,
We need to find the magnitude of induced emf at that instant. Induced emf is given by :
Where
is the magnetic flux,
, A is the area of cross section
So, the induced emf in the loop is 0.0603 volts. Hence, this is the required solution.
For problems especially pertaining motion, it is best to illustrate the problem to help you understand the problem. The picture I've attached is my illustration based on what I understood from the problem. Suppose the diamond in the picture is the nozzle. It is placed 1.5 m above the ground (bold horizontal line). The water coming out of the nozzle follows the direction of the arrows until it falls to the ground next to you holding the nozzle. When you turn it off, the water at the topmost part slowly comes back to the ground in 1.8 seconds.
Unfortunately, you weren't able to complete the problem. However, I would make a smart guess. I think it is logical that the problem would ask how high did the water shoot upwards from the nozzle, denoted as x. In order to solve this, we use the equations for free-falling objects:
t = √2h/g
1.8 = √2h/9.81
h = 15.9 m
To find the height of the water from the nozzle, we subtract the total height to 1.5 m to determine x.
x = 15.9 - 1.5 = 14.4 m
Unfortunately, you weren't able to complete the problem. However, I would make a smart guess. I think it is logical that the problem would ask how high did the water shoot upwards from the nozzle, denoted as x. In order to solve this, we use the equations for free-falling objects:
t = √2h/g
1.8 = √2h/9.81
h = 15.9 m
To find the height of the water from the nozzle, we subtract the total height to 1.5 m to determine x.
x = 15.9 - 1.5 = 14.4 m