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SpyIntel [72]
2 years ago
11

A basic cellular phone plan costs $ 18 per month for 50 calling minutes. Additional time costs $ 0.90 per minute. The formula Up

per C equals 18 plus 0.90 left parenthesis x minus 50 right parenthesis gives the monthly cost for this​ plan, C, for x calling​ minutes, where x greater than 50. How many calling minutes are possible for a monthly cost of at least $ 63 and at most $ 72 question mark
Mathematics
1 answer:
charle [14.2K]2 years ago
5 0

Answer:

There is a possibility of at least 100 calling minutes and at most 110 calling minutes.

Step-by-step explanation:

The given equation in words from the question is: C = 18 + 0.90 (x - 50)

This gives the formula for the Monthly Cost for the plan, C

The aim is to find the possible number of call minutes for the cost between $63 to $72.

So, we solve this first equation for the value of "x", putting C = $63

18 + 0.90 (x - 50) = 63

0.90 (x - 50) = 63 - 18 = 45

x - 50 = \frac{45}{0.90} = 50

x = 50 + 50 = 100 calling minutes

Next, we put C = $72, so that we have;

18 + 0.90 (x - 50) = 72

0.90 (x - 50) = 72 - 18 = 54

x - 50 = \frac{54}{0.90} = 60

x = 50 + 60 = 110 calling minutes

So, for a monthly cost of at least $ 63 and at most $ 72, there is a possibility of at least 100 calling minutes and at most 110 calling minutes.

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Answer:

Option 3

Step-by-step explanation:

The coordinates match it

4 0
2 years ago
Items for a fundraiser are packaged in small boxes shaped like rectangular prisms that are inches long, inches wide, and 8 inche
allochka39001 [22]

Answer:

- The number of small boxes that will fill the large box 1 = 64

- The number of small boxes that will fill the large box 2 = 56

Step-by-step explanation:

Complete Question

Items for a fundraiser are packaged in small boxes shaped like rectangular prisms that are 4.5 inches long, 4.5 inches wide, and 8 inches tall. To transport the items to an event, you want to know how many of the small boxes will fit in larger boxes. The larger boxes are available in two sizes. Large Box 1 is 24.25 inches long, 18 inches wide, and 24 inches tall. Large Box 2 is 20.5 inches long, 18.5 inches wide, and 24 inches tall. Both the small and large boxes must remain upright.

Solution

To know how many of the small boxes will fit in larger boxes, we need to obtain the volumes of the small box, large box 1 and large box 2.

Volume of a cuboid = L × W × H

For the small box,

Length = L = 4.5 inches

Width = W = 4.5 inches

Height = H = 8 inches

Volume of the small box = 4.5 × 4.5 × 8 = 162 in³

For large box 1,

Length = L = 24.25 inches

Width = W = 18 inches

Height = H = 24 inches

Volume of the large box 1 = 24.25 × 18 × 24 = 10,476 in³

For large box 2

Length = L = 20.5 inches

Width = W = 18.5 inches

Height = H = 24 inches

Volume of the large box 2 = 20.5 × 18.5 × 24 = 9,102 in³

The number of small boxes that'll fill the large box 1 = (10,476/162) = 64.667 = 64 small boxes (rounded down because the fraction cannot be forced into the large box 1.

The number of small boxes that will fill the large box 2 = (9,102/162) = 56.185 = 56 small boxes.

Hope this Helps!!!

7 0
2 years ago
Kamrynn is looking at her five quiz scores of 96 90 94 93 and 90. Determine the mean rounded to the nearest tenth median mode an
Romashka [77]

Answer:

Mean = 90, Median = 93, Mode = 90, Range = 6

Step-by-step explanation:

Mean:

96 + 90 + 94 + 93 + 90 = 463

463 ÷ 5 = 92.5

92.5 to nearest tenth = 90

Mean = 90

Median:

<em>90, 90</em>, <u>93</u>, <em>94 ,96</em>

Median = 93

Mode

<em>96, </em><u>90</u><em>, 94, 93, </em><u>90</u><em> </em>

Mode = 90

Range:

96 - 90 = 6

Range = 6

8 0
2 years ago
Can someone help me pls....
kogti [31]

Answer:

-1/3

Step-by-step explanation:

8 0
3 years ago
ND
Korvikt [17]

Step-by-step explanation:

As you have done till

3p + 8 = 20

3p = 20 - 8

3p = 12

p = 12 / 3 = 4

5 0
3 years ago
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