I’m thinking it’s gold because lead isn’t with cooper meaning that if u switch lead with cooper it won’t work at all .
Answer:
22.9 Liters CO(g) needed
Explanation:
2CO(g) + O₂(g) => 2CO₂(g)
? Liters 32.65g
= 32.65g/32g/mol
= 1.02 moles O₂
Rxn ratio for CO to O₂ = 2 mole CO(g) to 1 mole O₂(g)
∴moles CO(g) needed = 2 x 1.02 moles CO(g) = 2.04 moles CO(g)
Conditions of standard equation* is STP (0°C & 1atm) => 1 mole any gas occupies 22.4 Liters.
∴Volume of CO(g) = 1.02mole x 22.4Liters/mole = 22.9 Liters CO(g) needed
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*Standard Equation => molecular rxn balanced to smallest whole number ratio coefficients is assumed to be at STP conditions (0°C & 1atm).
The correct matches for changes of state are:
- 1 or 3 : Arrow that shows particles getting closer together
- gas: State of matter that would fill any container
- liquid: State of matter with definite volume but NOT shape
- 2 or 4: Arrow that shows particles gaining energy
- solid: State of matter with definite shape
<h3>What is change of state?</h3>
Change of state is the process whereby matter in one physical state is converted to matter in another state by the addition or removal of heat.
The process of change of state are:
- Melting: solid to liquid due to addition of heat
- Vaporization: liquid to gas due to addition of heat
- Sublimation: solid to gas due to addition of heat
- Freezing: liquid to solid due to removal of heat
- Condensation: gas to liquid due to removal of heat
- Deposition: gas to solid due to removal of heat
Considering the given diagram, the correct matches are:
- 1 or 3 : Arrow that shows particles getting closer together
- gas: State of matter that would fill any container
- liquid: State of matter with definite volume but NOT shape
- 2 or 4: Arrow that shows particles gaining energy
- solid: State of matter with definite shape
In conclusion, change of state of matter occurs due to heat changes.
Learn more about change of state at: brainly.com/question/1078692
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(a) One form of the Clausius-Clapeyron equation is
ln(P₂/P₁) = (ΔHv/R) * (1/T₁ - 1/T₂); where in this case:
Solving for ΔHv:
- ΔHv = R * ln(P₂/P₁) / (1/T₁ - 1/T₂)
- ΔHv = 8.31 J/molK * ln(5.3/1.3) / (1/358.96 - 1/392.46)
(b) <em>Normal boiling point means</em> that P = 1 atm = 101.325 kPa. We use the same formula, using the same values for P₁ and T₁, and replacing P₂ with atmosferic pressure, <u>solving for T₂</u>:
- ln(P₂/P₁) = (ΔHv/R) * (1/T₁ - 1/T₂)
- 1/T₂ = 1/T₁ - [ ln(P₂/P₁) / (ΔHv/R) ]
- 1/T₂ = 1/358.96 K - [ ln(101.325/1.3) / (49111.12/8.31) ]
(c)<em> The enthalpy of vaporization</em> was calculated in part (a), and it does not vary depending on temperature, meaning <u>that at the boiling point the enthalpy of vaporization ΔHv is still 49111.12 J/molK</u>.
Answer:
Thus, random error primarily affects precision. Typically, random error affects the last significant digit of a measurement. The main reasons for random error are limitations of instruments, environmental factors, and slight variations in procedure.
Explanation:
