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3 years ago

How mant atoms are in 3N2

Chemistry

2 answers:

geniusboy [140]3 years ago

8 0

Explanation:

you times 3 and 2 to get six.

Ainat [17]3 years ago

8 0

In 2 formula units of silver nitrate, there are 2 silver atoms, 2 nitrogen atoms, and 6 oxygen atoms. We can improve this answer by using the mole concept.

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Read the following chemical equation.

Anton [14]

Answer:

Bromine gains an electron

Explanation:

According to oxidation and reduction

8 0

3 years ago

Read 2 more answers

An iron ore sample weighing 0.5562 g is dissolved HCl (aq), and the iron is obtained as Fe2 in solution. This solution is then t

erik [133]

Answer:

$\% Fe^{+2}=70%$

Explanation:

Hello,

In this case, we could considering this as a redox titration:

$Fe^{+2}+(Cr_2O_7)^{-2}\rightarrow Fe^{+3}+Cr^{+3}$

Thus, the balance turns out (by adding both hydrogen ions and water):

$Fe^{+2}\rightarrow Fe^{+3}+1e^-\\(Cr_2^{+6}O_7)^{-2}+14H^++6e^-\rightarrow 2Cr^{+3}+7H_2O\\\\6Fe^{+2}+(Cr_2^{+6}O_7)^{-2}+14H^++6e^-\rightarrow Cr^{+3}+7H_2O+6Fe^{+3}+6e^-$

Thus, by stoichiometry, the grams of Fe+2 ions result:

$m_{Fe^{+2}}=0.04021\frac{molK_2Cr_2O_7}{L}*0.02872L*\frac{6molFe^{+2}}{1molK_2Cr_2O_7}*\frac{56gFe^{+2}}{1molFe^{+2}}=0.388gFe^{+2}$

Finally, the mass percent is:

$\% Fe^{+2}=\frac{0.388g}{0.5562g}*100\%\\ \% Fe^{+2}=70%$

Best regards.

8 0

2 years ago

____________ is refining the extracted raw metals into a purest form

Alex

Answer:

Extractive metallurgy

Explanation:

Extractive metallurgy is the practice of removing valuable metals from an ore and refining the extracted raw metals into a purer form.

8 0

2 years ago

1. Which of the following is an SI base unit for time? (2 points)

oee [108]

Number one would be Decades

6 0

3 years ago

Part 1. Determine the molar mass of a 0.622-gram sample of gas having a volume of 2.4 L at 287 K and 0.850 atm. Show your work.

zaharov [31]

If a sample of gas is a 0.622-gram, volume of 2.4 L at 287 K and 0.850 atm. Then the molar mass of the gas is 7.18 g/mol

<h3>What is an ideal gas equation?</h3>

The ideal gas law (PV = nRT) relates to the macroscopic properties of ideal gases.

An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

Given :

V = 2.4 L = 0.0024

P = 86126.25 Pa

T = 287 K

m = 0.622

R = 8.314

The ideal gas equation is given below.

n = PV/RT

n = 86126.25 x 0.0024 / 8.314 x 287

n = 0.622 / molar mass (n = Avogardos number)

Molar mass = 7.18 g

Hence, the molar mass of a 0.622-gram sample of gas having a volume of 2.4 L at 287 K and 0.850 atm is 7.18 g

More about the ideal gas equation link is given below.

brainly.com/question/4147359

#SPJ1

4 0

1 year ago