Question

How do I solve this?

Answer 1

Answer:

We'll solve that in parts.

The upper part is a right triangle that is 4 by (2 + 2 +6)

Area = (4 * 10) /2 = 20

The bottom of that figure is made of 3 parts.

A) a 2 by 2 right triangle. area equals  (2*2)/2 = 2

B) a 2 by 2 square whose area equals 2*2 = 4

C) a 6 by 2 right triangle whose area equals (6*2) / 2 = 6

Total Area = 20 + 2 + 4 + 6 = 32

Step-by-step explanation:

Answer 2

Answer:

The area of the figure is 32 units² .

Step-by-step explanation:

You can seperate the figures. In this diagram, there 3 triangles and 1 square. Then you have to calculate the area for each shape :

1st triangle (small shape),

$area = \frac{1}{2} \times base \times height$

Let base = 2 units,

Let height = 2 units,

$area = \frac{1}{2} \times 2 \times 2$

$area = 2 \: \: {units}^{2}$

2nd triangle (medium shape),

Let base = 2 units,

Let height = 6 units,

$area = \frac{1}{2} \times 2 \times 6$

$area = 6 \: \: {units}^{2}$

3rd triangle (large shape),

Let base = 10 units,

Let height = 4 units,

$area = \frac{1}{2} \times 10 \times 4$

$area = 20 \: \: {units}^{2}$

Square,

$area =base \times height$

Let base = 2 units,

Let height = 2 units,

$area = 2 \times 2$

$area = 4 \: \: {units}^{2}$

Lastly, you have to add up all the area of the shapes :

$area = 2 + 6 + 20 + 4$

$area = 32 \: \: {unit}^{2}$